1 
2 /*
3       Inverts 5 by 5 matrix using gaussian elimination with partial pivoting.
4 
5        Used by the sparse factorization routines in
6      src/mat/impls/baij/seq
7 
8        This is a combination of the Linpack routines
9     dgefa() and dgedi() specialized for a size of 5.
10 
11 */
12 #include <petscsys.h>
13 
PetscKernel_A_gets_inverse_A_5(MatScalar * a,PetscInt * ipvt,MatScalar * work,PetscReal shift,PetscBool allowzeropivot,PetscBool * zeropivotdetected)14 PETSC_EXTERN PetscErrorCode PetscKernel_A_gets_inverse_A_5(MatScalar *a,PetscInt *ipvt,MatScalar *work,PetscReal shift,PetscBool allowzeropivot,PetscBool *zeropivotdetected)
15 {
16   PetscInt  i__2,i__3,kp1,j,k,l,ll,i,kb,k3;
17   PetscInt  k4,j3;
18   MatScalar *aa,*ax,*ay,stmp;
19   MatReal   tmp,max;
20 
21   PetscFunctionBegin;
22   if (zeropivotdetected) *zeropivotdetected = PETSC_FALSE;
23   shift = .25*shift*(1.e-12 + PetscAbsScalar(a[0]) + PetscAbsScalar(a[6]) + PetscAbsScalar(a[12]) + PetscAbsScalar(a[18]) + PetscAbsScalar(a[24]));
24 
25   /* Parameter adjustments */
26   a -= 6;
27 
28   for (k = 1; k <= 4; ++k) {
29     kp1 = k + 1;
30     k3  = 5*k;
31     k4  = k3 + k;
32 
33     /* find l = pivot index */
34     i__2 = 6 - k;
35     aa   = &a[k4];
36     max  = PetscAbsScalar(aa[0]);
37     l    = 1;
38     for (ll=1; ll<i__2; ll++) {
39       tmp = PetscAbsScalar(aa[ll]);
40       if (tmp > max) { max = tmp; l = ll+1;}
41     }
42     l        += k - 1;
43     ipvt[k-1] = l;
44 
45     if (a[l + k3] == 0.0) {
46       if (shift == 0.0) {
47         if (allowzeropivot) {
48           PetscErrorCode ierr;
49           ierr = PetscInfo1(NULL,"Zero pivot, row %D\n",k-1);CHKERRQ(ierr);
50           *zeropivotdetected = PETSC_TRUE;
51         } else SETERRQ1(PETSC_COMM_SELF,PETSC_ERR_MAT_LU_ZRPVT,"Zero pivot, row %D",k-1);
52       } else {
53         /* SHIFT is applied to SINGLE diagonal entry; does this make any sense? */
54         a[l + k3] = shift;
55       }
56     }
57 
58     /* interchange if necessary */
59     if (l != k) {
60       stmp      = a[l + k3];
61       a[l + k3] = a[k4];
62       a[k4]     = stmp;
63     }
64 
65     /* compute multipliers */
66     stmp = -1. / a[k4];
67     i__2 = 5 - k;
68     aa   = &a[1 + k4];
69     for (ll=0; ll<i__2; ll++) aa[ll] *= stmp;
70 
71     /* row elimination with column indexing */
72     ax = &a[k4+1];
73     for (j = kp1; j <= 5; ++j) {
74       j3   = 5*j;
75       stmp = a[l + j3];
76       if (l != k) {
77         a[l + j3] = a[k + j3];
78         a[k + j3] = stmp;
79       }
80 
81       i__3 = 5 - k;
82       ay   = &a[1+k+j3];
83       for (ll=0; ll<i__3; ll++) ay[ll] += stmp*ax[ll];
84     }
85   }
86   ipvt[4] = 5;
87   if (a[30] == 0.0) {
88     if (allowzeropivot) {
89       PetscErrorCode ierr;
90       ierr = PetscInfo1(NULL,"Zero pivot, row %D\n",4);CHKERRQ(ierr);
91       *zeropivotdetected = PETSC_TRUE;
92     } else SETERRQ1(PETSC_COMM_SELF,PETSC_ERR_MAT_LU_ZRPVT,"Zero pivot, row %D",4);
93   }
94 
95   /* Now form the inverse */
96   /* compute inverse(u) */
97   for (k = 1; k <= 5; ++k) {
98     k3    = 5*k;
99     k4    = k3 + k;
100     a[k4] = 1.0 / a[k4];
101     stmp  = -a[k4];
102     i__2  = k - 1;
103     aa    = &a[k3 + 1];
104     for (ll=0; ll<i__2; ll++) aa[ll] *= stmp;
105     kp1 = k + 1;
106     if (5 < kp1) continue;
107     ax = aa;
108     for (j = kp1; j <= 5; ++j) {
109       j3        = 5*j;
110       stmp      = a[k + j3];
111       a[k + j3] = 0.0;
112       ay        = &a[j3 + 1];
113       for (ll=0; ll<k; ll++) ay[ll] += stmp*ax[ll];
114     }
115   }
116 
117   /* form inverse(u)*inverse(l) */
118   for (kb = 1; kb <= 4; ++kb) {
119     k   = 5 - kb;
120     k3  = 5*k;
121     kp1 = k + 1;
122     aa  = a + k3;
123     for (i = kp1; i <= 5; ++i) {
124       work[i-1] = aa[i];
125       aa[i]     = 0.0;
126     }
127     for (j = kp1; j <= 5; ++j) {
128       stmp   = work[j-1];
129       ax     = &a[5*j + 1];
130       ay     = &a[k3 + 1];
131       ay[0] += stmp*ax[0];
132       ay[1] += stmp*ax[1];
133       ay[2] += stmp*ax[2];
134       ay[3] += stmp*ax[3];
135       ay[4] += stmp*ax[4];
136     }
137     l = ipvt[k-1];
138     if (l != k) {
139       ax   = &a[k3 + 1];
140       ay   = &a[5*l + 1];
141       stmp = ax[0]; ax[0] = ay[0]; ay[0] = stmp;
142       stmp = ax[1]; ax[1] = ay[1]; ay[1] = stmp;
143       stmp = ax[2]; ax[2] = ay[2]; ay[2] = stmp;
144       stmp = ax[3]; ax[3] = ay[3]; ay[3] = stmp;
145       stmp = ax[4]; ax[4] = ay[4]; ay[4] = stmp;
146     }
147   }
148   PetscFunctionReturn(0);
149 }
150 
151