Searched refs:edgesInOrder (Results 1 – 2 of 2) sorted by relevance
29 private final List<E> edgesInOrder; field in Path44 edgesInOrder = new ArrayList<>(0); in Path()53 this.edgesInOrder = edgesInOrder; in Path()74 edgesInOrder.addAll(p.edgesInOrder); in Path()75 edgesInOrder.add(edge); in Path()103 edgesInOrder.addAll(p.edgesInOrder); in Path()104 edgesInOrder.addAll(edges); in Path()113 return edgesInOrder.size(); in length()133 edgesInOrder.add(edge); in Path()139 return edgesInOrder.equals(path.edgesInOrder); in pathsAreTheSame()[all …]
1223 Iterator<MultiSampleEdge> edgesInOrder = pivotalEdges.iterator(); in testCreateMapOfPivotalEdgesInTopoglogicalOrderBasicExample() local1228 while (edgesInOrder.hasNext()) { in testCreateMapOfPivotalEdgesInTopoglogicalOrderBasicExample()1229 MultiSampleEdge nextEdge = edgesInOrder.next(); in testCreateMapOfPivotalEdgesInTopoglogicalOrderBasicExample()1262 Iterator<MultiSampleEdge> edgesInOrder = pivotalEdges.iterator(); in testCreateMapOfPivotalEdgesInTopoglogicalOrderHiddenReferenceSequence() local1271 while (edgesInOrder.hasNext()) { in testCreateMapOfPivotalEdgesInTopoglogicalOrderHiddenReferenceSequence()1272 MultiSampleEdge nextEdge = edgesInOrder.next(); in testCreateMapOfPivotalEdgesInTopoglogicalOrderHiddenReferenceSequence()