Searched refs:lhsPrefix (Results 1 – 1 of 1) sorted by relevance
1466 Substring lhsPrefix; member1482 if (!Substring_HasPrefix(word, args->lhsPrefix) || in ModifyWord_SysVSubst()1497 word.start + Substring_Length(args->lhsPrefix), in ModifyWord_SysVSubst()3770 args.lhsPrefix = Substring_Init(lhs.start, in ApplyModifier_SysV()