Searched refs:SubRegisterIndex (Results 1 – 3 of 3) sorted by relevance
175 SubRegisterIndex, enumerator
390 return lexName(C, Token, MIToken::SubRegisterIndex, Rule.size(), in maybeLexSubRegisterIndex()
2221 assert(Token.is(MIToken::SubRegisterIndex)); in parseSubRegisterIndexOperand()2890 case MIToken::SubRegisterIndex: in parseMachineOperand()