xref: /openbsd/games/arithmetic/arithmetic.c (revision 3d8817e4)
1 /*	$OpenBSD: arithmetic.c,v 1.17 2009/10/27 23:59:23 deraadt Exp $	*/
2 
3 /*
4  * Copyright (c) 1989, 1993
5  *	The Regents of the University of California.  All rights reserved.
6  *
7  * This code is derived from software contributed to Berkeley by
8  * Eamonn McManus of Trinity College Dublin.
9  *
10  * Redistribution and use in source and binary forms, with or without
11  * modification, are permitted provided that the following conditions
12  * are met:
13  * 1. Redistributions of source code must retain the above copyright
14  *    notice, this list of conditions and the following disclaimer.
15  * 2. Redistributions in binary form must reproduce the above copyright
16  *    notice, this list of conditions and the following disclaimer in the
17  *    documentation and/or other materials provided with the distribution.
18  * 3. Neither the name of the University nor the names of its contributors
19  *    may be used to endorse or promote products derived from this software
20  *    without specific prior written permission.
21  *
22  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
23  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
24  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
25  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
26  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
27  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
28  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
29  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
30  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
31  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
32  * SUCH DAMAGE.
33  */
34 
35 /*
36  * By Eamonn McManus, Trinity College Dublin <emcmanus@cs.tcd.ie>.
37  *
38  * The operation of this program mimics that of the standard Unix game
39  * `arithmetic'.  I've made it as close as I could manage without examining
40  * the source code.  The principal differences are:
41  *
42  * The method of biasing towards numbers that had wrong answers in the past
43  * is different; original `arithmetic' seems to retain the bias forever,
44  * whereas this program lets the bias gradually decay as it is used.
45  *
46  * Original `arithmetic' delays for some period (3 seconds?) after printing
47  * the score.  I saw no reason for this delay, so I scrapped it.
48  *
49  * There is no longer a limitation on the maximum range that can be supplied
50  * to the program.  The original program required it to be less than 100.
51  * Anomalous results may occur with this program if ranges big enough to
52  * allow overflow are given.
53  *
54  * I have obviously not attempted to duplicate bugs in the original.  It
55  * would go into an infinite loop if invoked as `arithmetic / 0'.  It also
56  * did not recognise an EOF in its input, and would continue trying to read
57  * after it.  It did not check that the input was a valid number, treating any
58  * garbage as 0.  Finally, it did not flush stdout after printing its prompt,
59  * so in the unlikely event that stdout was not a terminal, it would not work
60  * properly.
61  */
62 
63 #include <sys/types.h>
64 #include <err.h>
65 #include <ctype.h>
66 #include <signal.h>
67 #include <stdio.h>
68 #include <stdlib.h>
69 #include <string.h>
70 #include <time.h>
71 #include <unistd.h>
72 
73 int	getrandom(int, int, int);
74 void	intr(int);
75 int	opnum(int);
76 void	penalise(int, int, int);
77 int	problem(void);
78 void	showstats(void);
79 void	usage(void);
80 
81 const char keylist[] = "+-x/";
82 const char defaultkeys[] = "+-";
83 const char *keys = defaultkeys;
84 int nkeys = sizeof(defaultkeys) - 1;
85 int rangemax = 10;
86 int nright, nwrong;
87 time_t qtime;
88 #define	NQUESTS	20
89 
90 /*
91  * Select keys from +-x/ to be asked addition, subtraction, multiplication,
92  * and division problems.  More than one key may be given.  The default is
93  * +-.  Specify a range to confine the operands to 0 - range.  Default upper
94  * bound is 10.  After every NQUESTS questions, statistics on the performance
95  * so far are printed.
96  */
97 int
98 main(int argc, char *argv[])
99 {
100 	extern char *optarg;
101 	extern int optind;
102 	int ch, cnt;
103 
104 	while ((ch = getopt(argc, argv, "hr:o:")) != -1)
105 		switch(ch) {
106 		case 'o': {
107 			const char *p;
108 
109 			for (p = keys = optarg; *p; ++p)
110 				if (!strchr(keylist, *p))
111 					errx(1, "unknown key.");
112 			nkeys = p - optarg;
113 			break;
114 		}
115 		case 'r':
116 			if ((rangemax = atoi(optarg)) <= 0)
117 				errx(1, "invalid range.");
118 			break;
119 		case '?':
120 		case 'h':
121 		default:
122 			usage();
123 		}
124 	if (argc -= optind)
125 		usage();
126 
127 	/* Seed the random-number generator. */
128 	srandomdev();
129 
130 	(void)signal(SIGINT, intr);
131 
132 	/* Now ask the questions. */
133 	for (;;) {
134 		for (cnt = NQUESTS; cnt--;)
135 			if (problem() == EOF)
136 				intr(0);   /* Print score and exit */
137 		showstats();
138 	}
139 	/* NOTREACHED */
140 }
141 
142 /* Handle interrupt character.  Print score and exit. */
143 void
144 intr(int dummy)
145 {
146 	showstats();
147 	exit(0);
148 }
149 
150 /* Print score.  Original `arithmetic' had a delay after printing it. */
151 void
152 showstats(void)
153 {
154 	if (nright + nwrong > 0) {
155 		(void)printf("\n\nRights %d; Wrongs %d; Score %d%%",
156 		    nright, nwrong, (int)(100L * nright / (nright + nwrong)));
157 		if (nright > 0)
158 	(void)printf("\nTotal time %ld seconds; %.1f seconds per problem\n\n",
159 			    (long)qtime, (float)qtime / nright);
160 	}
161 	(void)printf("\n");
162 }
163 
164 /*
165  * Pick a problem and ask it.  Keeps asking the same problem until supplied
166  * with the correct answer, or until EOF or interrupt is typed.  Problems are
167  * selected such that the right operand and either the left operand (for +, x)
168  * or the correct result (for -, /) are in the range 0 to rangemax.  Each wrong
169  * answer causes the numbers in the problem to be penalised, so that they are
170  * more likely to appear in subsequent problems.
171  */
172 int
173 problem(void)
174 {
175 	char *p;
176 	time_t start, finish;
177 	int left, op, right, result;
178 	char line[80];
179 
180 	op = keys[random() % nkeys];
181 	if (op != '/')
182 		right = getrandom(rangemax + 1, op, 1);
183 retry:
184 	/* Get the operands. */
185 	switch (op) {
186 	case '+':
187 		left = getrandom(rangemax + 1, op, 0);
188 		result = left + right;
189 		break;
190 	case '-':
191 		result = getrandom(rangemax + 1, op, 0);
192 		left = right + result;
193 		break;
194 	case 'x':
195 		left = getrandom(rangemax + 1, op, 0);
196 		result = left * right;
197 		break;
198 	case '/':
199 		right = getrandom(rangemax, op, 1) + 1;
200 		result = getrandom(rangemax + 1, op, 0);
201 		left = right * result + random() % right;
202 		break;
203 	}
204 
205 	/*
206 	 * A very big maxrange could cause negative values to pop
207 	 * up, owing to overflow.
208 	 */
209 	if (result < 0 || left < 0)
210 		goto retry;
211 
212 	(void)printf("%d %c %d =   ", left, op, right);
213 	(void)fflush(stdout);
214 	(void)time(&start);
215 
216 	/*
217 	 * Keep looping until the correct answer is given, or until EOF or
218 	 * interrupt is typed.
219 	 */
220 	for (;;) {
221 		if (!fgets(line, sizeof(line), stdin)) {
222 			(void)printf("\n");
223 			return(EOF);
224 		}
225 		for (p = line; isspace(*p); ++p);
226 		if (!isdigit(*p)) {
227 			(void)printf("Please type a number.\n");
228 			continue;
229 		}
230 		if (atoi(p) == result) {
231 			(void)printf("Right!\n");
232 			++nright;
233 			break;
234 		}
235 		/* Wrong answer; penalise and ask again. */
236 		(void)printf("What?\n");
237 		++nwrong;
238 		penalise(right, op, 1);
239 		if (op == 'x' || op == '+')
240 			penalise(left, op, 0);
241 		else
242 			penalise(result, op, 0);
243 	}
244 
245 	/*
246 	 * Accumulate the time taken.  Obviously rounding errors happen here;
247 	 * however they should cancel out, because some of the time you are
248 	 * charged for a partially elapsed second at the start, and some of
249 	 * the time you are not charged for a partially elapsed second at the
250 	 * end.
251 	 */
252 	(void)time(&finish);
253 	qtime += finish - start;
254 	return(0);
255 }
256 
257 /*
258  * Here is the code for accumulating penalties against the numbers for which
259  * a wrong answer was given.  The right operand and either the left operand
260  * (for +, x) or the result (for -, /) are stored in a list for the particular
261  * operation, and each becomes more likely to appear again in that operation.
262  * Initially, each number is charged a penalty of WRONGPENALTY, giving it that
263  * many extra chances of appearing.  Each time it is selected because of this,
264  * its penalty is decreased by one; it is removed when it reaches 0.
265  *
266  * The penalty[] array gives the sum of all penalties in the list for
267  * each operation and each operand.  The penlist[] array has the lists of
268  * penalties themselves.
269  */
270 
271 int penalty[sizeof(keylist) - 1][2];
272 struct penalty {
273 	int value, penalty;	/* Penalised value and its penalty. */
274 	struct penalty *next;
275 } *penlist[sizeof(keylist) - 1][2];
276 
277 #define	WRONGPENALTY	5	/* Perhaps this should depend on maxrange. */
278 
279 /*
280  * Add a penalty for the number `value' to the list for operation `op',
281  * operand number `operand' (0 or 1).  If we run out of memory, we just
282  * forget about the penalty (how likely is this, anyway?).
283  */
284 void
285 penalise(int value, int op, int operand)
286 {
287 	struct penalty *p;
288 
289 	op = opnum(op);
290 	if ((p = (struct penalty *)malloc((u_int)sizeof(*p))) == NULL)
291 		return;
292 	p->next = penlist[op][operand];
293 	penlist[op][operand] = p;
294 	penalty[op][operand] += p->penalty = WRONGPENALTY;
295 	p->value = value;
296 }
297 
298 /*
299  * Select a random value from 0 to maxval - 1 for operand `operand' (0 or 1)
300  * of operation `op'.  The random number we generate is either used directly
301  * as a value, or represents a position in the penalty list.  If the latter,
302  * we find the corresponding value and return that, decreasing its penalty.
303  */
304 int
305 getrandom(int maxval, int op, int operand)
306 {
307 	int value;
308 	struct penalty **pp, *p;
309 
310 	op = opnum(op);
311 	value = random() % (maxval + penalty[op][operand]);
312 
313 	/*
314 	 * 0 to maxval - 1 is a number to be used directly; bigger values
315 	 * are positions to be located in the penalty list.
316 	 */
317 	if (value < maxval)
318 		return(value);
319 	value -= maxval;
320 
321 	/*
322 	 * Find the penalty at position `value'; decrement its penalty and
323 	 * delete it if it reaches 0; return the corresponding value.
324 	 */
325 	for (pp = &penlist[op][operand]; (p = *pp) != NULL; pp = &p->next) {
326 		if (p->penalty > value) {
327 			value = p->value;
328 			penalty[op][operand]--;
329 			if (--(p->penalty) <= 0) {
330 				p = p->next;
331 				(void)free((char *)*pp);
332 				*pp = p;
333 			}
334 			return(value);
335 		}
336 		value -= p->penalty;
337 	}
338 	/*
339 	 * We can only get here if the value from the penalty[] array doesn't
340 	 * correspond to the actual sum of penalties in the list.  Provide an
341 	 * obscure message.
342 	 */
343 	errx(1, "bug: inconsistent penalties.");
344 	/* NOTREACHED */
345 }
346 
347 /* Return an index for the character op, which is one of [+-x/]. */
348 int
349 opnum(int op)
350 {
351 	char *p;
352 
353 	if (op == 0 || (p = strchr(keylist, op)) == NULL)
354 		errx(1, "bug: op %c not in keylist %s.", op, keylist);
355 	return(p - keylist);
356 }
357 
358 /* Print usage message and quit. */
359 void
360 usage(void)
361 {
362 	(void)fprintf(stderr, "usage: arithmetic [-o +-x/] [-r range]\n");
363 	exit(1);
364 }
365