xref: /openbsd/games/battlestar/parse.c (revision 274d7c50)
1 /*	$OpenBSD: parse.c,v 1.16 2015/12/31 17:51:19 mestre Exp $	*/
2 /*	$NetBSD: parse.c,v 1.3 1995/03/21 15:07:48 cgd Exp $	*/
3 
4 /*
5  * Copyright (c) 1983, 1993
6  *	The Regents of the University of California.  All rights reserved.
7  *
8  * Redistribution and use in source and binary forms, with or without
9  * modification, are permitted provided that the following conditions
10  * are met:
11  * 1. Redistributions of source code must retain the above copyright
12  *    notice, this list of conditions and the following disclaimer.
13  * 2. Redistributions in binary form must reproduce the above copyright
14  *    notice, this list of conditions and the following disclaimer in the
15  *    documentation and/or other materials provided with the distribution.
16  * 3. Neither the name of the University nor the names of its contributors
17  *    may be used to endorse or promote products derived from this software
18  *    without specific prior written permission.
19  *
20  * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND
21  * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
22  * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
23  * ARE DISCLAIMED.  IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE
24  * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
25  * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
26  * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
27  * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
28  * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
29  * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
30  * SUCH DAMAGE.
31  */
32 
33 #include <stdio.h>
34 #include <string.h>
35 
36 #include "extern.h"
37 
38 #define HASHSIZE	256
39 #define HASHMUL		81
40 #define HASHMASK	(HASHSIZE - 1)
41 
42 static int hash(const char *);
43 static void install(struct wlist *);
44 static struct wlist *lookup(const char *);
45 
46 struct wlist *hashtab[HASHSIZE];
47 
48 void
49 wordinit(void)
50 {
51 	struct wlist *w;
52 
53 	for (w = wlist; w->string; w++)
54 		install(w);
55 }
56 
57 static int
58 hash(const char *s)
59 {
60 	int     hashval = 0;
61 
62 	while (*s) {
63 		hashval += *s++;
64 		hashval *= HASHMUL;
65 		hashval &= HASHMASK;
66 	}
67 	return hashval;
68 }
69 
70 static struct wlist *
71 lookup(const char *s)
72 {
73 	struct wlist *wp;
74 
75 	for (wp = hashtab[hash(s)]; wp != NULL; wp = wp->next)
76 		if (*s == *wp->string && strcmp(s, wp->string) == 0)
77 			return wp;
78 	return NULL;
79 }
80 
81 static void
82 install(struct wlist *wp)
83 {
84 	int     hashval;
85 
86 	if (lookup(wp->string) == NULL) {
87 		hashval = hash(wp->string);
88 		wp->next = hashtab[hashval];
89 		hashtab[hashval] = wp;
90 	} else
91 		printf("Multiply defined %s.\n", wp->string);
92 }
93 
94 void
95 parse(void)
96 {
97 	struct wlist *wp;
98 	int     n;
99 	int     flag;
100 
101 	wordnumber = 0;		/* for cypher */
102 	for (n = 0; n <= wordcount; n++) {
103 		if ((wp = lookup(words[n])) == NULL) {
104 			wordvalue[n] = -1;
105 			wordtype[n] = -1;
106 		} else {
107 			wordvalue[n] = wp->value;
108 			wordtype[n] = wp->article;
109 		}
110 	}
111 	/* We never use adjectives, so yank them all; disambiguation
112 	 * code would need to go before this.
113 	 */
114 	for (n = 1; n < wordcount; n++)
115 		if (wordtype[n] == ADJS) {
116 			int i;
117 			for (i = n + 1; i <= wordcount; i++) {
118 				wordtype[i - 1] = wordtype[i];
119 				wordvalue[i - 1] = wordvalue[i];
120 				strlcpy(words[i - 1], words[i], WORDLEN);
121 			}
122 			wordcount--;
123 			n--;
124 		}
125 	/* Don't let a comma mean AND if followed by a verb. */
126 	for (n = 0; n < wordcount; n++)
127 		if (wordvalue[n] == AND && words[n][0] == ','
128 		    && wordtype[n + 1] == VERB) {
129 			wordvalue[n] = -1;
130 			wordtype[n] = -1;
131 		}
132 	/* Trim "AND AND" which can happen naturally at the end of a
133 	 * comma-delimited list.
134 	 */
135 	for (n = 1; n < wordcount; n++)
136 		if (wordvalue[n - 1] == AND && wordvalue[n] == AND) {
137 			int i;
138 			for (i = n + 1; i <= wordcount; i++) {
139 				wordtype[i - 1] = wordtype[i];
140 				wordvalue[i - 1] = wordvalue[i];
141 				strlcpy(words[i - 1], words[i], WORDLEN);
142 			}
143 			wordcount--;
144 		}
145 
146 	/* If there is a sequence (NOUN | OBJECT) AND EVERYTHING
147 	 * then move all the EVERYTHINGs to the beginning, since that's where
148 	 * they're expected.  We can't get rid of the NOUNs and OBJECTs in
149 	 * case they aren't in EVERYTHING (i.e. not here or nonexistent).
150 	 */
151 	flag = 1;
152 	while (flag) {
153 		flag = 0;
154 		for (n = 1; n < wordcount; n++)
155 			if ((wordtype[n - 1] == NOUNS || wordtype[n - 1] == OBJECT) &&
156 			    wordvalue[n] == AND && wordvalue[n + 1] == EVERYTHING) {
157 				char tmpword[WORDLEN];
158 				wordvalue[n + 1] = wordvalue[n - 1];
159 				wordvalue[n - 1] = EVERYTHING;
160 				wordtype[n + 1] = wordtype[n - 1];
161 				wordtype[n - 1] = OBJECT;
162 				strlcpy(tmpword, words[n - 1], WORDLEN);
163 				strlcpy(words[n - 1], words[n + 1], WORDLEN);
164 				strlcpy(words[n + 1], tmpword, WORDLEN);
165 				flag = 1;
166 		}
167 		/* And trim EVERYTHING AND EVERYTHING */
168 		for (n = 1; n < wordcount; n++)
169 			if (wordvalue[n - 1] == EVERYTHING &&
170 			    wordvalue[n] == AND && wordvalue[n + 1] == EVERYTHING) {
171 				int i;
172 				for (i = n + 1; i < wordcount; i++) {
173 					wordtype[i - 1] = wordtype[i + 1];
174 					wordvalue[i - 1] = wordvalue[i + 1];
175 					strlcpy(words[i - 1], words[i + 1], WORDLEN);
176 				}
177 				wordcount--;
178 				wordcount--;
179 				flag = 1;
180 			}
181 	}
182 }
183