1=head1 NAME 2 3perlpacktut - tutorial on C<pack> and C<unpack> 4 5=head1 DESCRIPTION 6 7C<pack> and C<unpack> are two functions for transforming data according 8to a user-defined template, between the guarded way Perl stores values 9and some well-defined representation as might be required in the 10environment of a Perl program. Unfortunately, they're also two of 11the most misunderstood and most often overlooked functions that Perl 12provides. This tutorial will demystify them for you. 13 14 15=head1 The Basic Principle 16 17Most programming languages don't shelter the memory where variables are 18stored. In C, for instance, you can take the address of some variable, 19and the C<sizeof> operator tells you how many bytes are allocated to 20the variable. Using the address and the size, you may access the storage 21to your heart's content. 22 23In Perl, you just can't access memory at random, but the structural and 24representational conversion provided by C<pack> and C<unpack> is an 25excellent alternative. The C<pack> function converts values to a byte 26sequence containing representations according to a given specification, 27the so-called "template" argument. C<unpack> is the reverse process, 28deriving some values from the contents of a string of bytes. (Be cautioned, 29however, that not all that has been packed together can be neatly unpacked - 30a very common experience as seasoned travellers are likely to confirm.) 31 32Why, you may ask, would you need a chunk of memory containing some values 33in binary representation? One good reason is input and output accessing 34some file, a device, or a network connection, whereby this binary 35representation is either forced on you or will give you some benefit 36in processing. Another cause is passing data to some system call that 37is not available as a Perl function: C<syscall> requires you to provide 38parameters stored in the way it happens in a C program. Even text processing 39(as shown in the next section) may be simplified with judicious usage 40of these two functions. 41 42To see how (un)packing works, we'll start with a simple template 43code where the conversion is in low gear: between the contents of a byte 44sequence and a string of hexadecimal digits. Let's use C<unpack>, since 45this is likely to remind you of a dump program, or some desperate last 46message unfortunate programs are wont to throw at you before they expire 47into the wild blue yonder. Assuming that the variable C<$mem> holds a 48sequence of bytes that we'd like to inspect without assuming anything 49about its meaning, we can write 50 51 my( $hex ) = unpack( 'H*', $mem ); 52 print "$hex\n"; 53 54whereupon we might see something like this, with each pair of hex digits 55corresponding to a byte: 56 57 41204d414e204120504c414e20412043414e414c2050414e414d41 58 59What was in this chunk of memory? Numbers, characters, or a mixture of 60both? Assuming that we're on a computer where ASCII (or some similar) 61encoding is used: hexadecimal values in the range C<0x40> - C<0x5A> 62indicate an uppercase letter, and C<0x20> encodes a space. So we might 63assume it is a piece of text, which some are able to read like a tabloid; 64but others will have to get hold of an ASCII table and relive that 65firstgrader feeling. Not caring too much about which way to read this, 66we note that C<unpack> with the template code C<H> converts the contents 67of a sequence of bytes into the customary hexadecimal notation. Since 68"a sequence of" is a pretty vague indication of quantity, C<H> has been 69defined to convert just a single hexadecimal digit unless it is followed 70by a repeat count. An asterisk for the repeat count means to use whatever 71remains. 72 73The inverse operation - packing byte contents from a string of hexadecimal 74digits - is just as easily written. For instance: 75 76 my $s = pack( 'H2' x 10, 30..39 ); 77 print "$s\n"; 78 79Since we feed a list of ten 2-digit hexadecimal strings to C<pack>, the 80pack template should contain ten pack codes. If this is run on a computer 81with ASCII character coding, it will print C<0123456789>. 82 83=head1 Packing Text 84 85Let's suppose you've got to read in a data file like this: 86 87 Date |Description | Income|Expenditure 88 01/24/2001 Zed's Camel Emporium 1147.99 89 01/28/2001 Flea spray 24.99 90 01/29/2001 Camel rides to tourists 235.00 91 92How do we do it? You might think first to use C<split>; however, since 93C<split> collapses blank fields, you'll never know whether a record was 94income or expenditure. Oops. Well, you could always use C<substr>: 95 96 while (<>) { 97 my $date = substr($_, 0, 11); 98 my $desc = substr($_, 12, 27); 99 my $income = substr($_, 40, 7); 100 my $expend = substr($_, 52, 7); 101 ... 102 } 103 104It's not really a barrel of laughs, is it? In fact, it's worse than it 105may seem; the eagle-eyed may notice that the first field should only be 10610 characters wide, and the error has propagated right through the other 107numbers - which we've had to count by hand. So it's error-prone as well 108as horribly unfriendly. 109 110Or maybe we could use regular expressions: 111 112 while (<>) { 113 my($date, $desc, $income, $expend) = 114 m|(\d\d/\d\d/\d{4}) (.{27}) (.{7})(.*)|; 115 ... 116 } 117 118Urgh. Well, it's a bit better, but - well, would you want to maintain 119that? 120 121Hey, isn't Perl supposed to make this sort of thing easy? Well, it does, 122if you use the right tools. C<pack> and C<unpack> are designed to help 123you out when dealing with fixed-width data like the above. Let's have a 124look at a solution with C<unpack>: 125 126 while (<>) { 127 my($date, $desc, $income, $expend) = unpack("A10xA27xA7A*", $_); 128 ... 129 } 130 131That looks a bit nicer; but we've got to take apart that weird template. 132Where did I pull that out of? 133 134OK, let's have a look at some of our data again; in fact, we'll include 135the headers, and a handy ruler so we can keep track of where we are. 136 137 1 2 3 4 5 138 1234567890123456789012345678901234567890123456789012345678 139 Date |Description | Income|Expenditure 140 01/28/2001 Flea spray 24.99 141 01/29/2001 Camel rides to tourists 235.00 142 143From this, we can see that the date column stretches from column 1 to 144column 10 - ten characters wide. The C<pack>-ese for "character" is 145C<A>, and ten of them are C<A10>. So if we just wanted to extract the 146dates, we could say this: 147 148 my($date) = unpack("A10", $_); 149 150OK, what's next? Between the date and the description is a blank column; 151we want to skip over that. The C<x> template means "skip forward", so we 152want one of those. Next, we have another batch of characters, from 12 to 15338. That's 27 more characters, hence C<A27>. (Don't make the fencepost 154error - there are 27 characters between 12 and 38, not 26. Count 'em!) 155 156Now we skip another character and pick up the next 7 characters: 157 158 my($date,$description,$income) = unpack("A10xA27xA7", $_); 159 160Now comes the clever bit. Lines in our ledger which are just income and 161not expenditure might end at column 46. Hence, we don't want to tell our 162C<unpack> pattern that we B<need> to find another 12 characters; we'll 163just say "if there's anything left, take it". As you might guess from 164regular expressions, that's what the C<*> means: "use everything 165remaining". 166 167=over 3 168 169=item * 170 171Be warned, though, that unlike regular expressions, if the C<unpack> 172template doesn't match the incoming data, Perl will scream and die. 173 174=back 175 176 177Hence, putting it all together: 178 179 my ($date, $description, $income, $expend) = 180 unpack("A10xA27xA7xA*", $_); 181 182Now, that's our data parsed. I suppose what we might want to do now is 183total up our income and expenditure, and add another line to the end of 184our ledger - in the same format - saying how much we've brought in and 185how much we've spent: 186 187 while (<>) { 188 my ($date, $desc, $income, $expend) = 189 unpack("A10xA27xA7xA*", $_); 190 $tot_income += $income; 191 $tot_expend += $expend; 192 } 193 194 $tot_income = sprintf("%.2f", $tot_income); # Get them into 195 $tot_expend = sprintf("%.2f", $tot_expend); # "financial" format 196 197 $date = POSIX::strftime("%m/%d/%Y", localtime); 198 199 # OK, let's go: 200 201 print pack("A10xA27xA7xA*", $date, "Totals", 202 $tot_income, $tot_expend); 203 204Oh, hmm. That didn't quite work. Let's see what happened: 205 206 01/24/2001 Zed's Camel Emporium 1147.99 207 01/28/2001 Flea spray 24.99 208 01/29/2001 Camel rides to tourists 1235.00 209 03/23/2001Totals 1235.001172.98 210 211OK, it's a start, but what happened to the spaces? We put C<x>, didn't 212we? Shouldn't it skip forward? Let's look at what L<perlfunc/pack> says: 213 214 x A null byte. 215 216Urgh. No wonder. There's a big difference between "a null byte", 217character zero, and "a space", character 32. Perl's put something 218between the date and the description - but unfortunately, we can't see 219it! 220 221What we actually need to do is expand the width of the fields. The C<A> 222format pads any non-existent characters with spaces, so we can use the 223additional spaces to line up our fields, like this: 224 225 print pack("A11 A28 A8 A*", $date, "Totals", 226 $tot_income, $tot_expend); 227 228(Note that you can put spaces in the template to make it more readable, 229but they don't translate to spaces in the output.) Here's what we got 230this time: 231 232 01/24/2001 Zed's Camel Emporium 1147.99 233 01/28/2001 Flea spray 24.99 234 01/29/2001 Camel rides to tourists 1235.00 235 03/23/2001 Totals 1235.00 1172.98 236 237That's a bit better, but we still have that last column which needs to 238be moved further over. There's an easy way to fix this up: 239unfortunately, we can't get C<pack> to right-justify our fields, but we 240can get C<sprintf> to do it: 241 242 $tot_income = sprintf("%.2f", $tot_income); 243 $tot_expend = sprintf("%12.2f", $tot_expend); 244 $date = POSIX::strftime("%m/%d/%Y", localtime); 245 print pack("A11 A28 A8 A*", $date, "Totals", 246 $tot_income, $tot_expend); 247 248This time we get the right answer: 249 250 01/28/2001 Flea spray 24.99 251 01/29/2001 Camel rides to tourists 1235.00 252 03/23/2001 Totals 1235.00 1172.98 253 254So that's how we consume and produce fixed-width data. Let's recap what 255we've seen of C<pack> and C<unpack> so far: 256 257=over 3 258 259=item * 260 261Use C<pack> to go from several pieces of data to one fixed-width 262version; use C<unpack> to turn a fixed-width-format string into several 263pieces of data. 264 265=item * 266 267The pack format C<A> means "any character"; if you're C<pack>ing and 268you've run out of things to pack, C<pack> will fill the rest up with 269spaces. 270 271=item * 272 273C<x> means "skip a byte" when C<unpack>ing; when C<pack>ing, it means 274"introduce a null byte" - that's probably not what you mean if you're 275dealing with plain text. 276 277=item * 278 279You can follow the formats with numbers to say how many characters 280should be affected by that format: C<A12> means "take 12 characters"; 281C<x6> means "skip 6 bytes" or "character 0, 6 times". 282 283=item * 284 285Instead of a number, you can use C<*> to mean "consume everything else 286left". 287 288B<Warning>: when packing multiple pieces of data, C<*> only means 289"consume all of the current piece of data". That's to say 290 291 pack("A*A*", $one, $two) 292 293packs all of C<$one> into the first C<A*> and then all of C<$two> into 294the second. This is a general principle: each format character 295corresponds to one piece of data to be C<pack>ed. 296 297=back 298 299 300 301=head1 Packing Numbers 302 303So much for textual data. Let's get onto the meaty stuff that C<pack> 304and C<unpack> are best at: handling binary formats for numbers. There is, 305of course, not just one binary format - life would be too simple - but 306Perl will do all the finicky labor for you. 307 308 309=head2 Integers 310 311Packing and unpacking numbers implies conversion to and from some 312I<specific> binary representation. Leaving floating point numbers 313aside for the moment, the salient properties of any such representation 314are: 315 316=over 4 317 318=item * 319 320the number of bytes used for storing the integer, 321 322=item * 323 324whether the contents are interpreted as a signed or unsigned number, 325 326=item * 327 328the byte ordering: whether the first byte is the least or most 329significant byte (or: little-endian or big-endian, respectively). 330 331=back 332 333So, for instance, to pack 20302 to a signed 16 bit integer in your 334computer's representation you write 335 336 my $ps = pack( 's', 20302 ); 337 338Again, the result is a string, now containing 2 bytes. If you print 339this string (which is, generally, not recommended) you might see 340C<ON> or C<NO> (depending on your system's byte ordering) - or something 341entirely different if your computer doesn't use ASCII character encoding. 342Unpacking C<$ps> with the same template returns the original integer value: 343 344 my( $s ) = unpack( 's', $ps ); 345 346This is true for all numeric template codes. But don't expect miracles: 347if the packed value exceeds the allotted byte capacity, high order bits 348are silently discarded, and unpack certainly won't be able to pull them 349back out of some magic hat. And, when you pack using a signed template 350code such as C<s>, an excess value may result in the sign bit 351getting set, and unpacking this will smartly return a negative value. 352 35316 bits won't get you too far with integers, but there is C<l> and C<L> 354for signed and unsigned 32-bit integers. And if this is not enough and 355your system supports 64 bit integers you can push the limits much closer 356to infinity with pack codes C<q> and C<Q>. A notable exception is provided 357by pack codes C<i> and C<I> for signed and unsigned integers of the 358"local custom" variety: Such an integer will take up as many bytes as 359a local C compiler returns for C<sizeof(int)>, but it'll use I<at least> 36032 bits. 361 362Each of the integer pack codes C<sSlLqQ> results in a fixed number of bytes, 363no matter where you execute your program. This may be useful for some 364applications, but it does not provide for a portable way to pass data 365structures between Perl and C programs (bound to happen when you call 366XS extensions or the Perl function C<syscall>), or when you read or 367write binary files. What you'll need in this case are template codes that 368depend on what your local C compiler compiles when you code C<short> or 369C<unsigned long>, for instance. These codes and their corresponding 370byte lengths are shown in the table below. Since the C standard leaves 371much leeway with respect to the relative sizes of these data types, actual 372values may vary, and that's why the values are given as expressions in 373C and Perl. (If you'd like to use values from C<%Config> in your program 374you have to import it with C<use Config>.) 375 376 signed unsigned byte length in C byte length in Perl 377 s! S! sizeof(short) $Config{shortsize} 378 i! I! sizeof(int) $Config{intsize} 379 l! L! sizeof(long) $Config{longsize} 380 q! Q! sizeof(long long) $Config{longlongsize} 381 382The C<i!> and C<I!> codes aren't different from C<i> and C<I>; they are 383tolerated for completeness' sake. 384 385 386=head2 Unpacking a Stack Frame 387 388Requesting a particular byte ordering may be necessary when you work with 389binary data coming from some specific architecture whereas your program could 390run on a totally different system. As an example, assume you have 24 bytes 391containing a stack frame as it happens on an Intel 8086: 392 393 +---------+ +----+----+ +---------+ 394 TOS: | IP | TOS+4:| FL | FH | FLAGS TOS+14:| SI | 395 +---------+ +----+----+ +---------+ 396 | CS | | AL | AH | AX | DI | 397 +---------+ +----+----+ +---------+ 398 | BL | BH | BX | BP | 399 +----+----+ +---------+ 400 | CL | CH | CX | DS | 401 +----+----+ +---------+ 402 | DL | DH | DX | ES | 403 +----+----+ +---------+ 404 405First, we note that this time-honored 16-bit CPU uses little-endian order, 406and that's why the low order byte is stored at the lower address. To 407unpack such a (unsigned) short we'll have to use code C<v>. A repeat 408count unpacks all 12 shorts: 409 410 my( $ip, $cs, $flags, $ax, $bx, $cd, $dx, $si, $di, $bp, $ds, $es ) = 411 unpack( 'v12', $frame ); 412 413Alternatively, we could have used C<C> to unpack the individually 414accessible byte registers FL, FH, AL, AH, etc.: 415 416 my( $fl, $fh, $al, $ah, $bl, $bh, $cl, $ch, $dl, $dh ) = 417 unpack( 'C10', substr( $frame, 4, 10 ) ); 418 419It would be nice if we could do this in one fell swoop: unpack a short, 420back up a little, and then unpack 2 bytes. Since Perl I<is> nice, it 421proffers the template code C<X> to back up one byte. Putting this all 422together, we may now write: 423 424 my( $ip, $cs, 425 $flags,$fl,$fh, 426 $ax,$al,$ah, $bx,$bl,$bh, $cx,$cl,$ch, $dx,$dl,$dh, 427 $si, $di, $bp, $ds, $es ) = 428 unpack( 'v2' . ('vXXCC' x 5) . 'v5', $frame ); 429 430(The clumsy construction of the template can be avoided - just read on!) 431 432We've taken some pains to construct the template so that it matches 433the contents of our frame buffer. Otherwise we'd either get undefined values, 434or C<unpack> could not unpack all. If C<pack> runs out of items, it will 435supply null strings (which are coerced into zeroes whenever the pack code 436says so). 437 438 439=head2 How to Eat an Egg on a Net 440 441The pack code for big-endian (high order byte at the lowest address) is 442C<n> for 16 bit and C<N> for 32 bit integers. You use these codes 443if you know that your data comes from a compliant architecture, but, 444surprisingly enough, you should also use these pack codes if you 445exchange binary data, across the network, with some system that you 446know next to nothing about. The simple reason is that this 447order has been chosen as the I<network order>, and all standard-fearing 448programs ought to follow this convention. (This is, of course, a stern 449backing for one of the Lilliputian parties and may well influence the 450political development there.) So, if the protocol expects you to send 451a message by sending the length first, followed by just so many bytes, 452you could write: 453 454 my $buf = pack( 'N', length( $msg ) ) . $msg; 455 456or even: 457 458 my $buf = pack( 'NA*', length( $msg ), $msg ); 459 460and pass C<$buf> to your send routine. Some protocols demand that the 461count should include the length of the count itself: then just add 4 462to the data length. (But make sure to read L<"Lengths and Widths"> before 463you really code this!) 464 465 466=head2 Byte-order modifiers 467 468In the previous sections we've learned how to use C<n>, C<N>, C<v> and 469C<V> to pack and unpack integers with big- or little-endian byte-order. 470While this is nice, it's still rather limited because it leaves out all 471kinds of signed integers as well as 64-bit integers. For example, if you 472wanted to unpack a sequence of signed big-endian 16-bit integers in a 473platform-independent way, you would have to write: 474 475 my @data = unpack 's*', pack 'S*', unpack 'n*', $buf; 476 477This is ugly. As of Perl 5.9.2, there's a much nicer way to express your 478desire for a certain byte-order: the C<E<gt>> and C<E<lt>> modifiers. 479C<E<gt>> is the big-endian modifier, while C<E<lt>> is the little-endian 480modifier. Using them, we could rewrite the above code as: 481 482 my @data = unpack 's>*', $buf; 483 484As you can see, the "big end" of the arrow touches the C<s>, which is a 485nice way to remember that C<E<gt>> is the big-endian modifier. The same 486obviously works for C<E<lt>>, where the "little end" touches the code. 487 488You will probably find these modifiers even more useful if you have 489to deal with big- or little-endian C structures. Be sure to read 490L<"Packing and Unpacking C Structures"> for more on that. 491 492 493=head2 Floating point Numbers 494 495For packing floating point numbers you have the choice between the 496pack codes C<f>, C<d>, C<F> and C<D>. C<f> and C<d> pack into (or unpack 497from) single-precision or double-precision representation as it is provided 498by your system. If your systems supports it, C<D> can be used to pack and 499unpack extended-precision floating point values (C<long double>), which 500can offer even more resolution than C<f> or C<d>. C<F> packs an C<NV>, 501which is the floating point type used by Perl internally. (There 502is no such thing as a network representation for reals, so if you want 503to send your real numbers across computer boundaries, you'd better stick 504to ASCII representation, unless you're absolutely sure what's on the other 505end of the line. For the even more adventuresome, you can use the byte-order 506modifiers from the previous section also on floating point codes.) 507 508 509 510=head1 Exotic Templates 511 512 513=head2 Bit Strings 514 515Bits are the atoms in the memory world. Access to individual bits may 516have to be used either as a last resort or because it is the most 517convenient way to handle your data. Bit string (un)packing converts 518between strings containing a series of C<0> and C<1> characters and 519a sequence of bytes each containing a group of 8 bits. This is almost 520as simple as it sounds, except that there are two ways the contents of 521a byte may be written as a bit string. Let's have a look at an annotated 522byte: 523 524 7 6 5 4 3 2 1 0 525 +-----------------+ 526 | 1 0 0 0 1 1 0 0 | 527 +-----------------+ 528 MSB LSB 529 530It's egg-eating all over again: Some think that as a bit string this should 531be written "10001100" i.e. beginning with the most significant bit, others 532insist on "00110001". Well, Perl isn't biased, so that's why we have two bit 533string codes: 534 535 $byte = pack( 'B8', '10001100' ); # start with MSB 536 $byte = pack( 'b8', '00110001' ); # start with LSB 537 538It is not possible to pack or unpack bit fields - just integral bytes. 539C<pack> always starts at the next byte boundary and "rounds up" to the 540next multiple of 8 by adding zero bits as required. (If you do want bit 541fields, there is L<perlfunc/vec>. Or you could implement bit field 542handling at the character string level, using split, substr, and 543concatenation on unpacked bit strings.) 544 545To illustrate unpacking for bit strings, we'll decompose a simple 546status register (a "-" stands for a "reserved" bit): 547 548 +-----------------+-----------------+ 549 | S Z - A - P - C | - - - - O D I T | 550 +-----------------+-----------------+ 551 MSB LSB MSB LSB 552 553Converting these two bytes to a string can be done with the unpack 554template C<'b16'>. To obtain the individual bit values from the bit 555string we use C<split> with the "empty" separator pattern which dissects 556into individual characters. Bit values from the "reserved" positions are 557simply assigned to C<undef>, a convenient notation for "I don't care where 558this goes". 559 560 ($carry, undef, $parity, undef, $auxcarry, undef, $zero, $sign, 561 $trace, $interrupt, $direction, $overflow) = 562 split( //, unpack( 'b16', $status ) ); 563 564We could have used an unpack template C<'b12'> just as well, since the 565last 4 bits can be ignored anyway. 566 567 568=head2 Uuencoding 569 570Another odd-man-out in the template alphabet is C<u>, which packs a 571"uuencoded string". ("uu" is short for Unix-to-Unix.) Chances are that 572you won't ever need this encoding technique which was invented to overcome 573the shortcomings of old-fashioned transmission mediums that do not support 574other than simple ASCII data. The essential recipe is simple: Take three 575bytes, or 24 bits. Split them into 4 six-packs, adding a space (0x20) to 576each. Repeat until all of the data is blended. Fold groups of 4 bytes into 577lines no longer than 60 and garnish them in front with the original byte count 578(incremented by 0x20) and a C<"\n"> at the end. - The C<pack> chef will 579prepare this for you, a la minute, when you select pack code C<u> on the menu: 580 581 my $uubuf = pack( 'u', $bindat ); 582 583A repeat count after C<u> sets the number of bytes to put into an 584uuencoded line, which is the maximum of 45 by default, but could be 585set to some (smaller) integer multiple of three. C<unpack> simply ignores 586the repeat count. 587 588 589=head2 Doing Sums 590 591An even stranger template code is C<%>E<lt>I<number>E<gt>. First, because 592it's used as a prefix to some other template code. Second, because it 593cannot be used in C<pack> at all, and third, in C<unpack>, doesn't return the 594data as defined by the template code it precedes. Instead it'll give you an 595integer of I<number> bits that is computed from the data value by 596doing sums. For numeric unpack codes, no big feat is achieved: 597 598 my $buf = pack( 'iii', 100, 20, 3 ); 599 print unpack( '%32i3', $buf ), "\n"; # prints 123 600 601For string values, C<%> returns the sum of the byte values saving 602you the trouble of a sum loop with C<substr> and C<ord>: 603 604 print unpack( '%32A*', "\x01\x10" ), "\n"; # prints 17 605 606Although the C<%> code is documented as returning a "checksum": 607don't put your trust in such values! Even when applied to a small number 608of bytes, they won't guarantee a noticeable Hamming distance. 609 610In connection with C<b> or C<B>, C<%> simply adds bits, and this can be put 611to good use to count set bits efficiently: 612 613 my $bitcount = unpack( '%32b*', $mask ); 614 615And an even parity bit can be determined like this: 616 617 my $evenparity = unpack( '%1b*', $mask ); 618 619 620=head2 Unicode 621 622Unicode is a character set that can represent most characters in most of 623the world's languages, providing room for over one million different 624characters. Unicode 3.1 specifies 94,140 characters: The Basic Latin 625characters are assigned to the numbers 0 - 127. The Latin-1 Supplement with 626characters that are used in several European languages is in the next 627range, up to 255. After some more Latin extensions we find the character 628sets from languages using non-Roman alphabets, interspersed with a 629variety of symbol sets such as currency symbols, Zapf Dingbats or Braille. 630(You might want to visit L<http://www.unicode.org/> for a look at some of 631them - my personal favourites are Telugu and Kannada.) 632 633The Unicode character sets associates characters with integers. Encoding 634these numbers in an equal number of bytes would more than double the 635requirements for storing texts written in Latin alphabets. 636The UTF-8 encoding avoids this by storing the most common (from a western 637point of view) characters in a single byte while encoding the rarer 638ones in three or more bytes. 639 640Perl uses UTF-8, internally, for most Unicode strings. 641 642So what has this got to do with C<pack>? Well, if you want to compose a 643Unicode string (that is internally encoded as UTF-8), you can do so by 644using template code C<U>. As an example, let's produce the Euro currency 645symbol (code number 0x20AC): 646 647 $UTF8{Euro} = pack( 'U', 0x20AC ); 648 # Equivalent to: $UTF8{Euro} = "\x{20ac}"; 649 650Inspecting C<$UTF8{Euro}> shows that it contains 3 bytes: 651"\xe2\x82\xac". However, it contains only 1 character, number 0x20AC. 652The round trip can be completed with C<unpack>: 653 654 $Unicode{Euro} = unpack( 'U', $UTF8{Euro} ); 655 656Unpacking using the C<U> template code also works on UTF-8 encoded byte 657strings. 658 659Usually you'll want to pack or unpack UTF-8 strings: 660 661 # pack and unpack the Hebrew alphabet 662 my $alefbet = pack( 'U*', 0x05d0..0x05ea ); 663 my @hebrew = unpack( 'U*', $utf ); 664 665Please note: in the general case, you're better off using 666Encode::decode_utf8 to decode a UTF-8 encoded byte string to a Perl 667Unicode string, and Encode::encode_utf8 to encode a Perl Unicode string 668to UTF-8 bytes. These functions provide means of handling invalid byte 669sequences and generally have a friendlier interface. 670 671=head2 Another Portable Binary Encoding 672 673The pack code C<w> has been added to support a portable binary data 674encoding scheme that goes way beyond simple integers. (Details can 675be found at L<http://Casbah.org/>, the Scarab project.) A BER (Binary Encoded 676Representation) compressed unsigned integer stores base 128 677digits, most significant digit first, with as few digits as possible. 678Bit eight (the high bit) is set on each byte except the last. There 679is no size limit to BER encoding, but Perl won't go to extremes. 680 681 my $berbuf = pack( 'w*', 1, 128, 128+1, 128*128+127 ); 682 683A hex dump of C<$berbuf>, with spaces inserted at the right places, 684shows 01 8100 8101 81807F. Since the last byte is always less than 685128, C<unpack> knows where to stop. 686 687 688=head1 Template Grouping 689 690Prior to Perl 5.8, repetitions of templates had to be made by 691C<x>-multiplication of template strings. Now there is a better way as 692we may use the pack codes C<(> and C<)> combined with a repeat count. 693The C<unpack> template from the Stack Frame example can simply 694be written like this: 695 696 unpack( 'v2 (vXXCC)5 v5', $frame ) 697 698Let's explore this feature a little more. We'll begin with the equivalent of 699 700 join( '', map( substr( $_, 0, 1 ), @str ) ) 701 702which returns a string consisting of the first character from each string. 703Using pack, we can write 704 705 pack( '(A)'.@str, @str ) 706 707or, because a repeat count C<*> means "repeat as often as required", 708simply 709 710 pack( '(A)*', @str ) 711 712(Note that the template C<A*> would only have packed C<$str[0]> in full 713length.) 714 715To pack dates stored as triplets ( day, month, year ) in an array C<@dates> 716into a sequence of byte, byte, short integer we can write 717 718 $pd = pack( '(CCS)*', map( @$_, @dates ) ); 719 720To swap pairs of characters in a string (with even length) one could use 721several techniques. First, let's use C<x> and C<X> to skip forward and back: 722 723 $s = pack( '(A)*', unpack( '(xAXXAx)*', $s ) ); 724 725We can also use C<@> to jump to an offset, with 0 being the position where 726we were when the last C<(> was encountered: 727 728 $s = pack( '(A)*', unpack( '(@1A @0A @2)*', $s ) ); 729 730Finally, there is also an entirely different approach by unpacking big 731endian shorts and packing them in the reverse byte order: 732 733 $s = pack( '(v)*', unpack( '(n)*', $s ); 734 735 736=head1 Lengths and Widths 737 738=head2 String Lengths 739 740In the previous section we've seen a network message that was constructed 741by prefixing the binary message length to the actual message. You'll find 742that packing a length followed by so many bytes of data is a 743frequently used recipe since appending a null byte won't work 744if a null byte may be part of the data. Here is an example where both 745techniques are used: after two null terminated strings with source and 746destination address, a Short Message (to a mobile phone) is sent after 747a length byte: 748 749 my $msg = pack( 'Z*Z*CA*', $src, $dst, length( $sm ), $sm ); 750 751Unpacking this message can be done with the same template: 752 753 ( $src, $dst, $len, $sm ) = unpack( 'Z*Z*CA*', $msg ); 754 755There's a subtle trap lurking in the offing: Adding another field after 756the Short Message (in variable C<$sm>) is all right when packing, but this 757cannot be unpacked naively: 758 759 # pack a message 760 my $msg = pack( 'Z*Z*CA*C', $src, $dst, length( $sm ), $sm, $prio ); 761 762 # unpack fails - $prio remains undefined! 763 ( $src, $dst, $len, $sm, $prio ) = unpack( 'Z*Z*CA*C', $msg ); 764 765The pack code C<A*> gobbles up all remaining bytes, and C<$prio> remains 766undefined! Before we let disappointment dampen the morale: Perl's got 767the trump card to make this trick too, just a little further up the sleeve. 768Watch this: 769 770 # pack a message: ASCIIZ, ASCIIZ, length/string, byte 771 my $msg = pack( 'Z* Z* C/A* C', $src, $dst, $sm, $prio ); 772 773 # unpack 774 ( $src, $dst, $sm, $prio ) = unpack( 'Z* Z* C/A* C', $msg ); 775 776Combining two pack codes with a slash (C</>) associates them with a single 777value from the argument list. In C<pack>, the length of the argument is 778taken and packed according to the first code while the argument itself 779is added after being converted with the template code after the slash. 780This saves us the trouble of inserting the C<length> call, but it is 781in C<unpack> where we really score: The value of the length byte marks the 782end of the string to be taken from the buffer. Since this combination 783doesn't make sense except when the second pack code isn't C<a*>, C<A*> 784or C<Z*>, Perl won't let you. 785 786The pack code preceding C</> may be anything that's fit to represent a 787number: All the numeric binary pack codes, and even text codes such as 788C<A4> or C<Z*>: 789 790 # pack/unpack a string preceded by its length in ASCII 791 my $buf = pack( 'A4/A*', "Humpty-Dumpty" ); 792 # unpack $buf: '13 Humpty-Dumpty' 793 my $txt = unpack( 'A4/A*', $buf ); 794 795C</> is not implemented in Perls before 5.6, so if your code is required to 796work on older Perls you'll need to C<unpack( 'Z* Z* C')> to get the length, 797then use it to make a new unpack string. For example 798 799 # pack a message: ASCIIZ, ASCIIZ, length, string, byte 800 # (5.005 compatible) 801 my $msg = pack( 'Z* Z* C A* C', $src, $dst, length $sm, $sm, $prio ); 802 803 # unpack 804 ( undef, undef, $len) = unpack( 'Z* Z* C', $msg ); 805 ($src, $dst, $sm, $prio) = unpack ( "Z* Z* x A$len C", $msg ); 806 807But that second C<unpack> is rushing ahead. It isn't using a simple literal 808string for the template. So maybe we should introduce... 809 810=head2 Dynamic Templates 811 812So far, we've seen literals used as templates. If the list of pack 813items doesn't have fixed length, an expression constructing the 814template is required (whenever, for some reason, C<()*> cannot be used). 815Here's an example: To store named string values in a way that can be 816conveniently parsed by a C program, we create a sequence of names and 817null terminated ASCII strings, with C<=> between the name and the value, 818followed by an additional delimiting null byte. Here's how: 819 820 my $env = pack( '(A*A*Z*)' . keys( %Env ) . 'C', 821 map( { ( $_, '=', $Env{$_} ) } keys( %Env ) ), 0 ); 822 823Let's examine the cogs of this byte mill, one by one. There's the C<map> 824call, creating the items we intend to stuff into the C<$env> buffer: 825to each key (in C<$_>) it adds the C<=> separator and the hash entry value. 826Each triplet is packed with the template code sequence C<A*A*Z*> that 827is repeated according to the number of keys. (Yes, that's what the C<keys> 828function returns in scalar context.) To get the very last null byte, 829we add a C<0> at the end of the C<pack> list, to be packed with C<C>. 830(Attentive readers may have noticed that we could have omitted the 0.) 831 832For the reverse operation, we'll have to determine the number of items 833in the buffer before we can let C<unpack> rip it apart: 834 835 my $n = $env =~ tr/\0// - 1; 836 my %env = map( split( /=/, $_ ), unpack( "(Z*)$n", $env ) ); 837 838The C<tr> counts the null bytes. The C<unpack> call returns a list of 839name-value pairs each of which is taken apart in the C<map> block. 840 841 842=head2 Counting Repetitions 843 844Rather than storing a sentinel at the end of a data item (or a list of items), 845we could precede the data with a count. Again, we pack keys and values of 846a hash, preceding each with an unsigned short length count, and up front 847we store the number of pairs: 848 849 my $env = pack( 'S(S/A* S/A*)*', scalar keys( %Env ), %Env ); 850 851This simplifies the reverse operation as the number of repetitions can be 852unpacked with the C</> code: 853 854 my %env = unpack( 'S/(S/A* S/A*)', $env ); 855 856Note that this is one of the rare cases where you cannot use the same 857template for C<pack> and C<unpack> because C<pack> can't determine 858a repeat count for a C<()>-group. 859 860 861=head2 Intel HEX 862 863Intel HEX is a file format for representing binary data, mostly for 864programming various chips, as a text file. (See 865L<http://en.wikipedia.org/wiki/.hex> for a detailed description, and 866L<http://en.wikipedia.org/wiki/SREC_(file_format)> for the Motorola 867S-record format, which can be unravelled using the same technique.) 868Each line begins with a colon (':') and is followed by a sequence of 869hexadecimal characters, specifying a byte count I<n> (8 bit), 870an address (16 bit, big endian), a record type (8 bit), I<n> data bytes 871and a checksum (8 bit) computed as the least significant byte of the two's 872complement sum of the preceding bytes. Example: C<:0300300002337A1E>. 873 874The first step of processing such a line is the conversion, to binary, 875of the hexadecimal data, to obtain the four fields, while checking the 876checksum. No surprise here: we'll start with a simple C<pack> call to 877convert everything to binary: 878 879 my $binrec = pack( 'H*', substr( $hexrec, 1 ) ); 880 881The resulting byte sequence is most convenient for checking the checksum. 882Don't slow your program down with a for loop adding the C<ord> values 883of this string's bytes - the C<unpack> code C<%> is the thing to use 884for computing the 8-bit sum of all bytes, which must be equal to zero: 885 886 die unless unpack( "%8C*", $binrec ) == 0; 887 888Finally, let's get those four fields. By now, you shouldn't have any 889problems with the first three fields - but how can we use the byte count 890of the data in the first field as a length for the data field? Here 891the codes C<x> and C<X> come to the rescue, as they permit jumping 892back and forth in the string to unpack. 893 894 my( $addr, $type, $data ) = unpack( "x n C X4 C x3 /a", $bin ); 895 896Code C<x> skips a byte, since we don't need the count yet. Code C<n> takes 897care of the 16-bit big-endian integer address, and C<C> unpacks the 898record type. Being at offset 4, where the data begins, we need the count. 899C<X4> brings us back to square one, which is the byte at offset 0. 900Now we pick up the count, and zoom forth to offset 4, where we are 901now fully furnished to extract the exact number of data bytes, leaving 902the trailing checksum byte alone. 903 904 905 906=head1 Packing and Unpacking C Structures 907 908In previous sections we have seen how to pack numbers and character 909strings. If it were not for a couple of snags we could conclude this 910section right away with the terse remark that C structures don't 911contain anything else, and therefore you already know all there is to it. 912Sorry, no: read on, please. 913 914If you have to deal with a lot of C structures, and don't want to 915hack all your template strings manually, you'll probably want to have 916a look at the CPAN module C<Convert::Binary::C>. Not only can it parse 917your C source directly, but it also has built-in support for all the 918odds and ends described further on in this section. 919 920=head2 The Alignment Pit 921 922In the consideration of speed against memory requirements the balance 923has been tilted in favor of faster execution. This has influenced the 924way C compilers allocate memory for structures: On architectures 925where a 16-bit or 32-bit operand can be moved faster between places in 926memory, or to or from a CPU register, if it is aligned at an even or 927multiple-of-four or even at a multiple-of eight address, a C compiler 928will give you this speed benefit by stuffing extra bytes into structures. 929If you don't cross the C shoreline this is not likely to cause you any 930grief (although you should care when you design large data structures, 931or you want your code to be portable between architectures (you do want 932that, don't you?)). 933 934To see how this affects C<pack> and C<unpack>, we'll compare these two 935C structures: 936 937 typedef struct { 938 char c1; 939 short s; 940 char c2; 941 long l; 942 } gappy_t; 943 944 typedef struct { 945 long l; 946 short s; 947 char c1; 948 char c2; 949 } dense_t; 950 951Typically, a C compiler allocates 12 bytes to a C<gappy_t> variable, but 952requires only 8 bytes for a C<dense_t>. After investigating this further, 953we can draw memory maps, showing where the extra 4 bytes are hidden: 954 955 0 +4 +8 +12 956 +--+--+--+--+--+--+--+--+--+--+--+--+ 957 |c1|xx| s |c2|xx|xx|xx| l | xx = fill byte 958 +--+--+--+--+--+--+--+--+--+--+--+--+ 959 gappy_t 960 961 0 +4 +8 962 +--+--+--+--+--+--+--+--+ 963 | l | h |c1|c2| 964 +--+--+--+--+--+--+--+--+ 965 dense_t 966 967And that's where the first quirk strikes: C<pack> and C<unpack> 968templates have to be stuffed with C<x> codes to get those extra fill bytes. 969 970The natural question: "Why can't Perl compensate for the gaps?" warrants 971an answer. One good reason is that C compilers might provide (non-ANSI) 972extensions permitting all sorts of fancy control over the way structures 973are aligned, even at the level of an individual structure field. And, if 974this were not enough, there is an insidious thing called C<union> where 975the amount of fill bytes cannot be derived from the alignment of the next 976item alone. 977 978OK, so let's bite the bullet. Here's one way to get the alignment right 979by inserting template codes C<x>, which don't take a corresponding item 980from the list: 981 982 my $gappy = pack( 'cxs cxxx l!', $c1, $s, $c2, $l ); 983 984Note the C<!> after C<l>: We want to make sure that we pack a long 985integer as it is compiled by our C compiler. And even now, it will only 986work for the platforms where the compiler aligns things as above. 987And somebody somewhere has a platform where it doesn't. 988[Probably a Cray, where C<short>s, C<int>s and C<long>s are all 8 bytes. :-)] 989 990Counting bytes and watching alignments in lengthy structures is bound to 991be a drag. Isn't there a way we can create the template with a simple 992program? Here's a C program that does the trick: 993 994 #include <stdio.h> 995 #include <stddef.h> 996 997 typedef struct { 998 char fc1; 999 short fs; 1000 char fc2; 1001 long fl; 1002 } gappy_t; 1003 1004 #define Pt(struct,field,tchar) \ 1005 printf( "@%d%s ", offsetof(struct,field), # tchar ); 1006 1007 int main() { 1008 Pt( gappy_t, fc1, c ); 1009 Pt( gappy_t, fs, s! ); 1010 Pt( gappy_t, fc2, c ); 1011 Pt( gappy_t, fl, l! ); 1012 printf( "\n" ); 1013 } 1014 1015The output line can be used as a template in a C<pack> or C<unpack> call: 1016 1017 my $gappy = pack( '@0c @2s! @4c @8l!', $c1, $s, $c2, $l ); 1018 1019Gee, yet another template code - as if we hadn't plenty. But 1020C<@> saves our day by enabling us to specify the offset from the beginning 1021of the pack buffer to the next item: This is just the value 1022the C<offsetof> macro (defined in C<E<lt>stddef.hE<gt>>) returns when 1023given a C<struct> type and one of its field names ("member-designator" in 1024C standardese). 1025 1026Neither using offsets nor adding C<x>'s to bridge the gaps is satisfactory. 1027(Just imagine what happens if the structure changes.) What we really need 1028is a way of saying "skip as many bytes as required to the next multiple of N". 1029In fluent Templatese, you say this with C<x!N> where N is replaced by the 1030appropriate value. Here's the next version of our struct packaging: 1031 1032 my $gappy = pack( 'c x!2 s c x!4 l!', $c1, $s, $c2, $l ); 1033 1034That's certainly better, but we still have to know how long all the 1035integers are, and portability is far away. Rather than C<2>, 1036for instance, we want to say "however long a short is". But this can be 1037done by enclosing the appropriate pack code in brackets: C<[s]>. So, here's 1038the very best we can do: 1039 1040 my $gappy = pack( 'c x![s] s c x![l!] l!', $c1, $s, $c2, $l ); 1041 1042 1043=head2 Dealing with Endian-ness 1044 1045Now, imagine that we want to pack the data for a machine with a 1046different byte-order. First, we'll have to figure out how big the data 1047types on the target machine really are. Let's assume that the longs are 104832 bits wide and the shorts are 16 bits wide. You can then rewrite the 1049template as: 1050 1051 my $gappy = pack( 'c x![s] s c x![l] l', $c1, $s, $c2, $l ); 1052 1053If the target machine is little-endian, we could write: 1054 1055 my $gappy = pack( 'c x![s] s< c x![l] l<', $c1, $s, $c2, $l ); 1056 1057This forces the short and the long members to be little-endian, and is 1058just fine if you don't have too many struct members. But we could also 1059use the byte-order modifier on a group and write the following: 1060 1061 my $gappy = pack( '( c x![s] s c x![l] l )<', $c1, $s, $c2, $l ); 1062 1063This is not as short as before, but it makes it more obvious that we 1064intend to have little-endian byte-order for a whole group, not only 1065for individual template codes. It can also be more readable and easier 1066to maintain. 1067 1068 1069=head2 Alignment, Take 2 1070 1071I'm afraid that we're not quite through with the alignment catch yet. The 1072hydra raises another ugly head when you pack arrays of structures: 1073 1074 typedef struct { 1075 short count; 1076 char glyph; 1077 } cell_t; 1078 1079 typedef cell_t buffer_t[BUFLEN]; 1080 1081Where's the catch? Padding is neither required before the first field C<count>, 1082nor between this and the next field C<glyph>, so why can't we simply pack 1083like this: 1084 1085 # something goes wrong here: 1086 pack( 's!a' x @buffer, 1087 map{ ( $_->{count}, $_->{glyph} ) } @buffer ); 1088 1089This packs C<3*@buffer> bytes, but it turns out that the size of 1090C<buffer_t> is four times C<BUFLEN>! The moral of the story is that 1091the required alignment of a structure or array is propagated to the 1092next higher level where we have to consider padding I<at the end> 1093of each component as well. Thus the correct template is: 1094 1095 pack( 's!ax' x @buffer, 1096 map{ ( $_->{count}, $_->{glyph} ) } @buffer ); 1097 1098=head2 Alignment, Take 3 1099 1100And even if you take all the above into account, ANSI still lets this: 1101 1102 typedef struct { 1103 char foo[2]; 1104 } foo_t; 1105 1106vary in size. The alignment constraint of the structure can be greater than 1107any of its elements. [And if you think that this doesn't affect anything 1108common, dismember the next cellphone that you see. Many have ARM cores, and 1109the ARM structure rules make C<sizeof (foo_t)> == 4] 1110 1111=head2 Pointers for How to Use Them 1112 1113The title of this section indicates the second problem you may run into 1114sooner or later when you pack C structures. If the function you intend 1115to call expects a, say, C<void *> value, you I<cannot> simply take 1116a reference to a Perl variable. (Although that value certainly is a 1117memory address, it's not the address where the variable's contents are 1118stored.) 1119 1120Template code C<P> promises to pack a "pointer to a fixed length string". 1121Isn't this what we want? Let's try: 1122 1123 # allocate some storage and pack a pointer to it 1124 my $memory = "\x00" x $size; 1125 my $memptr = pack( 'P', $memory ); 1126 1127But wait: doesn't C<pack> just return a sequence of bytes? How can we pass this 1128string of bytes to some C code expecting a pointer which is, after all, 1129nothing but a number? The answer is simple: We have to obtain the numeric 1130address from the bytes returned by C<pack>. 1131 1132 my $ptr = unpack( 'L!', $memptr ); 1133 1134Obviously this assumes that it is possible to typecast a pointer 1135to an unsigned long and vice versa, which frequently works but should not 1136be taken as a universal law. - Now that we have this pointer the next question 1137is: How can we put it to good use? We need a call to some C function 1138where a pointer is expected. The read(2) system call comes to mind: 1139 1140 ssize_t read(int fd, void *buf, size_t count); 1141 1142After reading L<perlfunc> explaining how to use C<syscall> we can write 1143this Perl function copying a file to standard output: 1144 1145 require 'syscall.ph'; # run h2ph to generate this file 1146 sub cat($){ 1147 my $path = shift(); 1148 my $size = -s $path; 1149 my $memory = "\x00" x $size; # allocate some memory 1150 my $ptr = unpack( 'L', pack( 'P', $memory ) ); 1151 open( F, $path ) || die( "$path: cannot open ($!)\n" ); 1152 my $fd = fileno(F); 1153 my $res = syscall( &SYS_read, fileno(F), $ptr, $size ); 1154 print $memory; 1155 close( F ); 1156 } 1157 1158This is neither a specimen of simplicity nor a paragon of portability but 1159it illustrates the point: We are able to sneak behind the scenes and 1160access Perl's otherwise well-guarded memory! (Important note: Perl's 1161C<syscall> does I<not> require you to construct pointers in this roundabout 1162way. You simply pass a string variable, and Perl forwards the address.) 1163 1164How does C<unpack> with C<P> work? Imagine some pointer in the buffer 1165about to be unpacked: If it isn't the null pointer (which will smartly 1166produce the C<undef> value) we have a start address - but then what? 1167Perl has no way of knowing how long this "fixed length string" is, so 1168it's up to you to specify the actual size as an explicit length after C<P>. 1169 1170 my $mem = "abcdefghijklmn"; 1171 print unpack( 'P5', pack( 'P', $mem ) ); # prints "abcde" 1172 1173As a consequence, C<pack> ignores any number or C<*> after C<P>. 1174 1175 1176Now that we have seen C<P> at work, we might as well give C<p> a whirl. 1177Why do we need a second template code for packing pointers at all? The 1178answer lies behind the simple fact that an C<unpack> with C<p> promises 1179a null-terminated string starting at the address taken from the buffer, 1180and that implies a length for the data item to be returned: 1181 1182 my $buf = pack( 'p', "abc\x00efhijklmn" ); 1183 print unpack( 'p', $buf ); # prints "abc" 1184 1185 1186 1187Albeit this is apt to be confusing: As a consequence of the length being 1188implied by the string's length, a number after pack code C<p> is a repeat 1189count, not a length as after C<P>. 1190 1191 1192Using C<pack(..., $x)> with C<P> or C<p> to get the address where C<$x> is 1193actually stored must be used with circumspection. Perl's internal machinery 1194considers the relation between a variable and that address as its very own 1195private matter and doesn't really care that we have obtained a copy. Therefore: 1196 1197=over 4 1198 1199=item * 1200 1201Do not use C<pack> with C<p> or C<P> to obtain the address of variable 1202that's bound to go out of scope (and thereby freeing its memory) before you 1203are done with using the memory at that address. 1204 1205=item * 1206 1207Be very careful with Perl operations that change the value of the 1208variable. Appending something to the variable, for instance, might require 1209reallocation of its storage, leaving you with a pointer into no-man's land. 1210 1211=item * 1212 1213Don't think that you can get the address of a Perl variable 1214when it is stored as an integer or double number! C<pack('P', $x)> will 1215force the variable's internal representation to string, just as if you 1216had written something like C<$x .= ''>. 1217 1218=back 1219 1220It's safe, however, to P- or p-pack a string literal, because Perl simply 1221allocates an anonymous variable. 1222 1223 1224 1225=head1 Pack Recipes 1226 1227Here are a collection of (possibly) useful canned recipes for C<pack> 1228and C<unpack>: 1229 1230 # Convert IP address for socket functions 1231 pack( "C4", split /\./, "123.4.5.6" ); 1232 1233 # Count the bits in a chunk of memory (e.g. a select vector) 1234 unpack( '%32b*', $mask ); 1235 1236 # Determine the endianness of your system 1237 $is_little_endian = unpack( 'c', pack( 's', 1 ) ); 1238 $is_big_endian = unpack( 'xc', pack( 's', 1 ) ); 1239 1240 # Determine the number of bits in a native integer 1241 $bits = unpack( '%32I!', ~0 ); 1242 1243 # Prepare argument for the nanosleep system call 1244 my $timespec = pack( 'L!L!', $secs, $nanosecs ); 1245 1246For a simple memory dump we unpack some bytes into just as 1247many pairs of hex digits, and use C<map> to handle the traditional 1248spacing - 16 bytes to a line: 1249 1250 my $i; 1251 print map( ++$i % 16 ? "$_ " : "$_\n", 1252 unpack( 'H2' x length( $mem ), $mem ) ), 1253 length( $mem ) % 16 ? "\n" : ''; 1254 1255 1256=head1 Funnies Section 1257 1258 # Pulling digits out of nowhere... 1259 print unpack( 'C', pack( 'x' ) ), 1260 unpack( '%B*', pack( 'A' ) ), 1261 unpack( 'H', pack( 'A' ) ), 1262 unpack( 'A', unpack( 'C', pack( 'A' ) ) ), "\n"; 1263 1264 # One for the road ;-) 1265 my $advice = pack( 'all u can in a van' ); 1266 1267 1268=head1 Authors 1269 1270Simon Cozens and Wolfgang Laun. 1271 1272