1#include <stdlib.h>
2#include <string.h>
3#include <stdlib.h>
4#include <stdio.h>
5
6exec sql include ../regression;
7
8exec sql whenever sqlerror sqlprint;
9
10int
11main(void)
12{
13exec sql begin declare section;
14	int amount[8];
15	int increment=100;
16	char name[8][8];
17	char letter[8][1];
18	char command[128];
19exec sql end declare section;
20	int i,j;
21
22	ECPGdebug(1, stderr);
23
24	exec sql connect to REGRESSDB1 as main;
25
26	exec sql create table test (name char(8), amount int, letter char(1));
27	exec sql commit;
28
29	sprintf(command, "insert into test (name, amount, letter) values ('db: ''r1''', 1, 'f')");
30	exec sql execute immediate :command;
31
32	sprintf(command, "insert into test (name, amount, letter) values ('db: ''r1''', 2, 't')");
33	exec sql execute immediate :command;
34
35	sprintf(command, "insert into test (name, amount, letter) select name, amount+10, letter from test");
36	exec sql execute immediate :command;
37
38	printf("Inserted %ld tuples via execute immediate\n", sqlca.sqlerrd[2]);
39
40	sprintf(command, "insert into test (name, amount, letter) select name, amount+$1, letter from test");
41	exec sql prepare I from :command;
42	exec sql execute I using :increment;
43
44	printf("Inserted %ld tuples via prepared execute\n", sqlca.sqlerrd[2]);
45
46	exec sql commit;
47
48	sprintf (command, "select * from test");
49
50	exec sql prepare F from :command;
51	exec sql declare CUR cursor for F;
52
53	exec sql open CUR;
54	exec sql fetch 8 in CUR into :name, :amount, :letter;
55
56	for (i=0, j=sqlca.sqlerrd[2]; i<j; i++)
57	{
58		char n[8], l = letter[i][0];
59		int a = amount[i];
60
61		strncpy(n, name[i], 8);
62		printf("name[%d]=%8.8s\tamount[%d]=%d\tletter[%d]=%c\n", i, n, i, a, i, l);
63	}
64
65	exec sql close CUR;
66
67	sprintf (command, "select * from test where ? = amount");
68
69	exec sql prepare F from :command;
70	exec sql declare CUR3 cursor for F;
71
72	exec sql open CUR3 using 1;
73	exec sql fetch in CUR3 into :name, :amount, :letter;
74
75	for (i=0, j=sqlca.sqlerrd[2]; i<j; i++)
76	{
77		char n[8], l = letter[i][0];
78		int a = amount[i];
79
80		strncpy(n, name[i], 8);
81		printf("name[%d]=%8.8s\tamount[%d]=%d\tletter[%d]=%c\n", i, n, i, a, i, l);
82	}
83
84	exec sql close CUR3;
85	exec sql drop table test;
86	exec sql commit;
87	exec sql disconnect;
88
89	return 0;
90}
91