1 #include <u.h>
2 #include <libc.h>
3 #include <bio.h>
4 #include "diff.h"
5 
6 /*	diff - differential file comparison
7 *
8 *	Uses an algorithm due to Harold Stone, which finds
9 *	a pair of longest identical subsequences in the two
10 *	files.
11 *
12 *	The major goal is to generate the match vector J.
13 *	J[i] is the index of the line in file1 corresponding
14 *	to line i file0. J[i] = 0 if there is no
15 *	such line in file1.
16 *
17 *	Lines are hashed so as to work in core. All potential
18 *	matches are located by sorting the lines of each file
19 *	on the hash (called value). In particular, this
20 *	collects the equivalence classes in file1 together.
21 *	Subroutine equiv replaces the value of each line in
22 *	file0 by the index of the first element of its
23 *	matching equivalence in (the reordered) file1.
24 *	To save space equiv squeezes file1 into a single
25 *	array member in which the equivalence classes
26 *	are simply concatenated, except that their first
27 *	members are flagged by changing sign.
28 *
29 *	Next the indices that point into member are unsorted into
30 *	array class according to the original order of file0.
31 *
32 *	The cleverness lies in routine stone. This marches
33 *	through the lines of file0, developing a vector klist
34 *	of "k-candidates". At step i a k-candidate is a matched
35 *	pair of lines x,y (x in file0 y in file1) such that
36 *	there is a common subsequence of lenght k
37 *	between the first i lines of file0 and the first y
38 *	lines of file1, but there is no such subsequence for
39 *	any smaller y. x is the earliest possible mate to y
40 *	that occurs in such a subsequence.
41 *
42 *	Whenever any of the members of the equivalence class of
43 *	lines in file1 matable to a line in file0 has serial number
44 *	less than the y of some k-candidate, that k-candidate
45 *	with the smallest such y is replaced. The new
46 *	k-candidate is chained (via pred) to the current
47 *	k-1 candidate so that the actual subsequence can
48 *	be recovered. When a member has serial number greater
49 *	that the y of all k-candidates, the klist is extended.
50 *	At the end, the longest subsequence is pulled out
51 *	and placed in the array J by unravel.
52 *
53 *	With J in hand, the matches there recorded are
54 *	check'ed against reality to assure that no spurious
55 *	matches have crept in due to hashing. If they have,
56 *	they are broken, and "jackpot " is recorded--a harmless
57 *	matter except that a true match for a spuriously
58 *	mated line may now be unnecessarily reported as a change.
59 *
60 *	Much of the complexity of the program comes simply
61 *	from trying to minimize core utilization and
62 *	maximize the range of doable problems by dynamically
63 *	allocating what is needed and reusing what is not.
64 *	The core requirements for problems larger than somewhat
65 *	are (in words) 2*length(file0) + length(file1) +
66 *	3*(number of k-candidates installed),  typically about
67 *	6n words for files of length n.
68 */
69 /* TIDY THIS UP */
70 struct cand {
71 	int x;
72 	int y;
73 	int pred;
74 } cand;
75 struct line {
76 	int serial;
77 	int value;
78 } *file[2], line;
79 int len[2];
80 int binary;
81 struct line *sfile[2];	/*shortened by pruning common prefix and suffix*/
82 int slen[2];
83 int pref, suff;	/*length of prefix and suffix*/
84 int *class;	/*will be overlaid on file[0]*/
85 int *member;	/*will be overlaid on file[1]*/
86 int *klist;		/*will be overlaid on file[0] after class*/
87 struct cand *clist;	/* merely a free storage pot for candidates */
88 int clen;
89 int *J;		/*will be overlaid on class*/
90 long *ixold;	/*will be overlaid on klist*/
91 long *ixnew;	/*will be overlaid on file[1]*/
92 /* END OF SOME TIDYING */
93 
94 static void
sort(struct line * a,int n)95 sort(struct line *a, int n)	/*shellsort CACM #201*/
96 {
97 	int m;
98 	struct line *ai, *aim, *j, *k;
99 	struct line w;
100 	int i;
101 
102 	m = 0;
103 	for (i = 1; i <= n; i *= 2)
104 		m = 2*i - 1;
105 	for (m /= 2; m != 0; m /= 2) {
106 		k = a+(n-m);
107 		for (j = a+1; j <= k; j++) {
108 			ai = j;
109 			aim = ai+m;
110 			do {
111 				if (aim->value > ai->value ||
112 				   aim->value == ai->value &&
113 				   aim->serial > ai->serial)
114 					break;
115 				w = *ai;
116 				*ai = *aim;
117 				*aim = w;
118 
119 				aim = ai;
120 				ai -= m;
121 			} while (ai > a && aim >= ai);
122 		}
123 	}
124 }
125 
126 static void
unsort(struct line * f,int l,int * b)127 unsort(struct line *f, int l, int *b)
128 {
129 	int *a;
130 	int i;
131 
132 	a = MALLOC(int, (l+1));
133 	for(i=1;i<=l;i++)
134 		a[f[i].serial] = f[i].value;
135 	for(i=1;i<=l;i++)
136 		b[i] = a[i];
137 	FREE(a);
138 }
139 
140 static void
prune(void)141 prune(void)
142 {
143 	int i,j;
144 
145 	for(pref=0;pref<len[0]&&pref<len[1]&&
146 		file[0][pref+1].value==file[1][pref+1].value;
147 		pref++ ) ;
148 	for(suff=0;suff<len[0]-pref&&suff<len[1]-pref&&
149 		file[0][len[0]-suff].value==file[1][len[1]-suff].value;
150 		suff++) ;
151 	for(j=0;j<2;j++) {
152 		sfile[j] = file[j]+pref;
153 		slen[j] = len[j]-pref-suff;
154 		for(i=0;i<=slen[j];i++)
155 			sfile[j][i].serial = i;
156 	}
157 }
158 
159 static void
equiv(struct line * a,int n,struct line * b,int m,int * c)160 equiv(struct line *a, int n, struct line *b, int m, int *c)
161 {
162 	int i, j;
163 
164 	i = j = 1;
165 	while(i<=n && j<=m) {
166 		if(a[i].value < b[j].value)
167 			a[i++].value = 0;
168 		else if(a[i].value == b[j].value)
169 			a[i++].value = j;
170 		else
171 			j++;
172 	}
173 	while(i <= n)
174 		a[i++].value = 0;
175 	b[m+1].value = 0;
176 	j = 0;
177 	while(++j <= m) {
178 		c[j] = -b[j].serial;
179 		while(b[j+1].value == b[j].value) {
180 			j++;
181 			c[j] = b[j].serial;
182 		}
183 	}
184 	c[j] = -1;
185 }
186 
187 static int
newcand(int x,int y,int pred)188 newcand(int x, int  y, int pred)
189 {
190 	struct cand *q;
191 
192 	clist = REALLOC(clist, struct cand, (clen+1));
193 	q = clist + clen;
194 	q->x = x;
195 	q->y = y;
196 	q->pred = pred;
197 	return clen++;
198 }
199 
200 static int
search(int * c,int k,int y)201 search(int *c, int k, int y)
202 {
203 	int i, j, l;
204 	int t;
205 
206 	if(clist[c[k]].y < y)	/*quick look for typical case*/
207 		return k+1;
208 	i = 0;
209 	j = k+1;
210 	while((l=(i+j)/2) > i) {
211 		t = clist[c[l]].y;
212 		if(t > y)
213 			j = l;
214 		else if(t < y)
215 			i = l;
216 		else
217 			return l;
218 	}
219 	return l+1;
220 }
221 
222 static int
stone(int * a,int n,int * b,int * c)223 stone(int *a, int n, int *b, int *c)
224 {
225 	int i, k,y;
226 	int j, l;
227 	int oldc, tc;
228 	int oldl;
229 
230 	k = 0;
231 	c[0] = newcand(0,0,0);
232 	for(i=1; i<=n; i++) {
233 		j = a[i];
234 		if(j==0)
235 			continue;
236 		y = -b[j];
237 		oldl = 0;
238 		oldc = c[0];
239 		do {
240 			if(y <= clist[oldc].y)
241 				continue;
242 			l = search(c, k, y);
243 			if(l!=oldl+1)
244 				oldc = c[l-1];
245 			if(l<=k) {
246 				if(clist[c[l]].y <= y)
247 					continue;
248 				tc = c[l];
249 				c[l] = newcand(i,y,oldc);
250 				oldc = tc;
251 				oldl = l;
252 			} else {
253 				c[l] = newcand(i,y,oldc);
254 				k++;
255 				break;
256 			}
257 		} while((y=b[++j]) > 0);
258 	}
259 	return k;
260 }
261 
262 static void
unravel(int p)263 unravel(int p)
264 {
265 	int i;
266 	struct cand *q;
267 
268 	for(i=0; i<=len[0]; i++) {
269 		if (i <= pref)
270 			J[i] = i;
271 		else if (i > len[0]-suff)
272 			J[i] = i+len[1]-len[0];
273 		else
274 			J[i] = 0;
275 	}
276 	for(q=clist+p;q->y!=0;q=clist+q->pred)
277 		J[q->x+pref] = q->y+pref;
278 }
279 
280 static void
output(void)281 output(void)
282 {
283 	int m, i0, i1, j0, j1;
284 
285 	m = len[0];
286 	J[0] = 0;
287 	J[m+1] = len[1]+1;
288 	if (mode != 'e') {
289 		for (i0 = 1; i0 <= m; i0 = i1+1) {
290 			while (i0 <= m && J[i0] == J[i0-1]+1)
291 				i0++;
292 			j0 = J[i0-1]+1;
293 			i1 = i0-1;
294 			while (i1 < m && J[i1+1] == 0)
295 				i1++;
296 			j1 = J[i1+1]-1;
297 			J[i1] = j1;
298 			change(i0, i1, j0, j1);
299 		}
300 	}
301 	else {
302 		for (i0 = m; i0 >= 1; i0 = i1-1) {
303 			while (i0 >= 1 && J[i0] == J[i0+1]-1 && J[i0])
304 				i0--;
305 			j0 = J[i0+1]-1;
306 			i1 = i0+1;
307 			while (i1 > 1 && J[i1-1] == 0)
308 				i1--;
309 			j1 = J[i1-1]+1;
310 			J[i1] = j1;
311 			change(i1 , i0, j1, j0);
312 		}
313 	}
314 	if (m == 0)
315 		change(1, 0, 1, len[1]);
316 	flushchanges();
317 }
318 
319 #define BUF 4096
320 static int
cmp(Biobuf * b1,Biobuf * b2)321 cmp(Biobuf* b1, Biobuf* b2)
322 {
323 	int n;
324 	uchar buf1[BUF], buf2[BUF];
325 	int f1, f2;
326 	vlong nc = 1;
327 	uchar *b1s, *b1e, *b2s, *b2e;
328 
329 	f1 = Bfildes(b1);
330 	f2 = Bfildes(b2);
331 	seek(f1, 0, 0);
332 	seek(f2, 0, 0);
333 	b1s = b1e = buf1;
334 	b2s = b2e = buf2;
335 	for(;;){
336 		if(b1s >= b1e){
337 			if(b1s >= &buf1[BUF])
338 				b1s = buf1;
339 			n = read(f1, b1s,  &buf1[BUF] - b1s);
340 			b1e = b1s + n;
341 		}
342 		if(b2s >= b2e){
343 			if(b2s >= &buf2[BUF])
344 				b2s = buf2;
345 			n = read(f2, b2s,  &buf2[BUF] - b2s);
346 			b2e = b2s + n;
347 		}
348 		n = b2e - b2s;
349 		if(n > b1e - b1s)
350 			n = b1e - b1s;
351 		if(n <= 0)
352 			break;
353 		if(memcmp((void *)b1s, (void *)b2s, n) != 0){
354 			return 1;
355 		}
356 		nc += n;
357 		b1s += n;
358 		b2s += n;
359 	}
360 	if(b1e - b1s == b2e - b2s)
361 		return 0;
362 	return 1;
363 }
364 
365 void
diffreg(char * f,char * t)366 diffreg(char *f, char *t)
367 {
368 	Biobuf *b0, *b1;
369 	int k;
370 
371 	binary = 0;
372 	b0 = prepare(0, f);
373 	if (!b0)
374 		return;
375 	b1 = prepare(1, t);
376 	if (!b1) {
377 		FREE(file[0]);
378 		Bterm(b0);
379 		return;
380 	}
381 	if (binary){
382 		/* could use b0 and b1 but this is simpler. */
383 		if (cmp(b0, b1))
384 			print("binary files %s %s differ\n", f, t);
385 		Bterm(b0);
386 		Bterm(b1);
387 		return;
388 	}
389 	clen = 0;
390 	prune();
391 	sort(sfile[0], slen[0]);
392 	sort(sfile[1], slen[1]);
393 
394 	member = (int *)file[1];
395 	equiv(sfile[0], slen[0], sfile[1], slen[1], member);
396 	member = REALLOC(member, int, slen[1]+2);
397 
398 	class = (int *)file[0];
399 	unsort(sfile[0], slen[0], class);
400 	class = REALLOC(class, int, slen[0]+2);
401 
402 	klist = MALLOC(int, slen[0]+2);
403 	clist = MALLOC(struct cand, 1);
404 	k = stone(class, slen[0], member, klist);
405 	FREE(member);
406 	FREE(class);
407 
408 	J = MALLOC(int, len[0]+2);
409 	unravel(klist[k]);
410 	FREE(clist);
411 	FREE(klist);
412 
413 	ixold = MALLOC(long, len[0]+2);
414 	ixnew = MALLOC(long, len[1]+2);
415 	Bseek(b0, 0, 0); Bseek(b1, 0, 0);
416 	check(b0, b1);
417 	output();
418 	FREE(J); FREE(ixold); FREE(ixnew);
419 	Bterm(b0); Bterm(b1);			/* ++++ */
420 }
421