1 /*
2  * Copyright (c) 2011, Oracle and/or its affiliates. All rights reserved.
3  * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
4  *
5  * This code is free software; you can redistribute it and/or modify it
6  * under the terms of the GNU General Public License version 2 only, as
7  * published by the Free Software Foundation.
8  *
9  * This code is distributed in the hope that it will be useful, but WITHOUT
10  * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
11  * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
12  * version 2 for more details (a copy is included in the LICENSE file that
13  * accompanied this code).
14  *
15  * You should have received a copy of the GNU General Public License version
16  * 2 along with this work; if not, write to the Free Software Foundation,
17  * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
18  *
19  * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
20  * or visit www.oracle.com if you need additional information or have any
21  * questions.
22  */
23 
24 /*
25  * @test
26  * @bug 7040104
27  * @summary javac NPE on Object a[]; Object o = (a=null)[0];
28  */
29 
30 public class T7040104 {
main(String[] args)31     public static void main(String[] args) {
32         T7040104 t = new T7040104();
33         t.test1();
34         t.test2();
35         t.test3();
36         if (t.npeCount != 3) {
37             throw new AssertionError();
38         }
39     }
40 
41     int npeCount = 0;
42 
test1()43     void test1() {
44         Object a[];
45         try {
46             Object o = (a = null)[0];
47         }
48         catch (NullPointerException npe) {
49             npeCount++;
50         }
51     }
52 
test2()53     void test2() {
54         Object a[][];
55         try {
56             Object o = (a = null)[0][0];
57         }
58         catch (NullPointerException npe) {
59             npeCount++;
60         }
61     }
62 
test3()63     void test3() {
64         Object a[][][];
65         try {
66             Object o = (a = null)[0][0][0];
67         }
68         catch (NullPointerException npe) {
69             npeCount++;
70         }
71     }
72 }
73