1 extern char buf1[10]; 2 extern char buf2[10]; 3 extern void b(int i, int j, int w); 4 a()5void a() { 6 int i,j; 7 char *p; 8 int w; 9 10 p = buf1; 11 for(j = 0;j < 10; j++) { 12 for(i = 0;i < 10; i++) { 13 w = *p; 14 if(w != 1) { 15 w = buf2[p - buf1]; 16 b(i*2+1, j, w); 17 } 18 p++; 19 } 20 } 21 } 22