1 #include <stdio.h>
2 #include <string.h>
3 #include <pcre.h>
4
5 /* Compile thuswise:
6 gcc -Wall pcredemo.c -I/opt/local/include -L/opt/local/lib \
7 -R/opt/local/lib -lpcre
8 */
9
10 #define OVECCOUNT 30 /* should be a multiple of 3 */
11
main(int argc,char ** argv)12 int main(int argc, char **argv)
13 {
14 pcre *re;
15 const char *error;
16 int erroffset;
17 int ovector[OVECCOUNT];
18 int rc, i;
19
20 if (argc != 3)
21 {
22 printf("Two arguments required: a regex and a subject string\n");
23 return 1;
24 }
25
26 /* Compile the regular expression in the first argument */
27
28 re = pcre_compile(
29 argv[1], /* the pattern */
30 0, /* default options */
31 &error, /* for error message */
32 &erroffset, /* for error offset */
33 NULL); /* use default character tables */
34
35 /* Compilation failed: print the error message and exit */
36
37 if (re == NULL)
38 {
39 printf("PCRE compilation failed at offset %d: %s\n", erroffset, error);
40 return 1;
41 }
42
43 /* Compilation succeeded: match the subject in the second argument */
44
45 rc = pcre_exec(
46 re, /* the compiled pattern */
47 NULL, /* no extra data - we didn't study the pattern */
48 argv[2], /* the subject string */
49 (int)strlen(argv[2]), /* the length of the subject */
50 0, /* start at offset 0 in the subject */
51 0, /* default options */
52 ovector, /* output vector for substring information */
53 OVECCOUNT); /* number of elements in the output vector */
54
55 /* Matching failed: handle error cases */
56
57 if (rc < 0)
58 {
59 switch(rc)
60 {
61 case PCRE_ERROR_NOMATCH: printf("No match\n"); break;
62 /*
63 Handle other special cases if you like
64 */
65 default: printf("Matching error %d\n", rc); break;
66 }
67 return 1;
68 }
69
70 /* Match succeded */
71
72 printf("Match succeeded\n");
73
74 /* The output vector wasn't big enough */
75
76 if (rc == 0)
77 {
78 rc = OVECCOUNT/3;
79 printf("ovector only has room for %d captured substrings\n", rc - 1);
80 }
81
82 /* Show substrings stored in the output vector */
83
84 for (i = 0; i < rc; i++)
85 {
86 char *substring_start = argv[2] + ovector[2*i];
87 int substring_length = ovector[2*i+1] - ovector[2*i];
88 printf("%2d: %.*s\n", i, substring_length, substring_start);
89 }
90
91 return 0;
92 }
93
94
95