1 /*
2  * Copyright 2004 Sun Microsystems, Inc.  All rights reserved.
3  * Use is subject to license terms.
4  */
5 
6 #pragma ident	"%Z%%M%	%I%	%E% SMI"
7 
8 /*
9  * Copyright (C) 1998 by the FundsXpress, INC.
10  *
11  * All rights reserved.
12  *
13  * Export of this software from the United States of America may require
14  * a specific license from the United States Government.  It is the
15  * responsibility of any person or organization contemplating export to
16  * obtain such a license before exporting.
17  *
18  * WITHIN THAT CONSTRAINT, permission to use, copy, modify, and
19  * distribute this software and its documentation for any purpose and
20  * without fee is hereby granted, provided that the above copyright
21  * notice appear in all copies and that both that copyright notice and
22  * this permission notice appear in supporting documentation, and that
23  * the name of FundsXpress. not be used in advertising or publicity pertaining
24  * to distribution of the software without specific, written prior
25  * permission.  FundsXpress makes no representations about the suitability of
26  * this software for any purpose.  It is provided "as is" without express
27  * or implied warranty.
28  *
29  * THIS SOFTWARE IS PROVIDED ``AS IS'' AND WITHOUT ANY EXPRESS OR
30  * IMPLIED WARRANTIES, INCLUDING, WITHOUT LIMITATION, THE IMPLIED
31  * WARRANTIES OF MERCHANTIBILITY AND FITNESS FOR A PARTICULAR PURPOSE.
32  */
33 
34 #include <k5-int.h>
35 
36 /*
37  * Solaris Kerberos defines memory management macros in <krb5.h>,
38  * which is included by <k5-int.h>, so we need not include <memory.h>
39  */
40 /* #include <memory.h> */
41 
42 /*
43 n-fold(k-bits):
44   l = lcm(n,k)
45   r = l/k
46   s = k-bits | k-bits rot 13 | k-bits rot 13*2 | ... | k-bits rot 13*(r-1)
47   compute the 1's complement sum:
48 	n-fold = s[0..n-1]+s[n..2n-1]+s[2n..3n-1]+..+s[(k-1)*n..k*n-1]
49 */
50 
51 /* representation: msb first, assume n and k are multiples of 8, and
52    that k>=16.  this is the case of all the cryptosystems which are
53    likely to be used.  this function can be replaced if that
54    assumption ever fails.  */
55 
56 /* input length is in bits */
57 
58 void
59 krb5_nfold(inbits, in, outbits, out)
60      int inbits;
61      krb5_const unsigned char *in;
62      int outbits;
63      unsigned char *out;
64 {
65     int a,b,c,lcm;
66     int byte, i, msbit;
67 
68     /* the code below is more readable if I make these bytes
69        instead of bits */
70 
71     inbits >>= 3;
72     outbits >>= 3;
73 
74     /* first compute lcm(n,k) */
75 
76     a = outbits;
77     b = inbits;
78 
79     while(b != 0) {
80 	c = b;
81 	b = a%b;
82 	a = c;
83     }
84 
85     lcm = outbits*inbits/a;
86 
87     /* now do the real work */
88 
89     (void) memset(out, 0, outbits);
90     byte = 0;
91 
92     /* this will end up cycling through k lcm(k,n)/k times, which
93        is correct */
94     for (i=lcm-1; i>=0; i--) {
95 	/* compute the msbit in k which gets added into this byte */
96 	msbit = (/* first, start with the msbit in the first, unrotated
97 		    byte */
98 		 ((inbits<<3)-1)
99 		 /* then, for each byte, shift to the right for each
100 		    repetition */
101 		 +(((inbits<<3)+13)*(i/inbits))
102 		 /* last, pick out the correct byte within that
103 		    shifted repetition */
104 		 +((inbits-(i%inbits))<<3)
105 		 )%(inbits<<3);
106 
107 	/* pull out the byte value itself */
108 	byte += (((in[((inbits-1)-(msbit>>3))%inbits]<<8)|
109 		  (in[((inbits)-(msbit>>3))%inbits]))
110 		 >>((msbit&7)+1))&0xff;
111 
112 	/* do the addition */
113 	byte += out[i%outbits];
114 	out[i%outbits] = byte&0xff;
115 
116 #if 0
117 	printf("msbit[%d] = %d\tbyte = %02x\tsum = %03x\n", i, msbit,
118 	       (((in[((inbits-1)-(msbit>>3))%inbits]<<8)|
119 		 (in[((inbits)-(msbit>>3))%inbits]))
120 		>>((msbit&7)+1))&0xff, byte);
121 #endif
122 
123 	/* keep around the carry bit, if any */
124 	byte >>= 8;
125 
126 #if 0
127 	printf("carry=%d\n", byte);
128 #endif
129     }
130 
131     /* if there's a carry bit left over, add it back in */
132     if (byte) {
133 	for (i=outbits-1; i>=0; i--) {
134 	    /* do the addition */
135 	    byte += out[i];
136 	    out[i] = byte&0xff;
137 
138 	    /* keep around the carry bit, if any */
139 	    byte >>= 8;
140 	}
141     }
142 }
143 
144