xref: /openbsd/gnu/usr.bin/perl/pod/perlreftut.pod (revision 76d0caae)
1=head1 NAME
2
3perlreftut - Mark's very short tutorial about references
4
5=head1 DESCRIPTION
6
7One of the most important new features in Perl 5 was the capability to
8manage complicated data structures like multidimensional arrays and
9nested hashes.  To enable these, Perl 5 introduced a feature called
10I<references>, and using references is the key to managing complicated,
11structured data in Perl.  Unfortunately, there's a lot of funny syntax
12to learn, and the main manual page can be hard to follow.  The manual
13is quite complete, and sometimes people find that a problem, because
14it can be hard to tell what is important and what isn't.
15
16Fortunately, you only need to know 10% of what's in the main page to get
1790% of the benefit.  This page will show you that 10%.
18
19=head1 Who Needs Complicated Data Structures?
20
21One problem that comes up all the time is needing a hash whose values are
22lists.  Perl has hashes, of course, but the values have to be scalars;
23they can't be lists.
24
25Why would you want a hash of lists?  Let's take a simple example: You
26have a file of city and country names, like this:
27
28	Chicago, USA
29	Frankfurt, Germany
30	Berlin, Germany
31	Washington, USA
32	Helsinki, Finland
33	New York, USA
34
35and you want to produce an output like this, with each country mentioned
36once, and then an alphabetical list of the cities in that country:
37
38	Finland: Helsinki.
39	Germany: Berlin, Frankfurt.
40	USA:  Chicago, New York, Washington.
41
42The natural way to do this is to have a hash whose keys are country
43names.  Associated with each country name key is a list of the cities in
44that country.  Each time you read a line of input, split it into a country
45and a city, look up the list of cities already known to be in that
46country, and append the new city to the list.  When you're done reading
47the input, iterate over the hash as usual, sorting each list of cities
48before you print it out.
49
50If hash values couldn't be lists, you lose.  You'd probably have to
51combine all the cities into a single string somehow, and then when
52time came to write the output, you'd have to break the string into a
53list, sort the list, and turn it back into a string.  This is messy
54and error-prone.  And it's frustrating, because Perl already has
55perfectly good lists that would solve the problem if only you could
56use them.
57
58=head1 The Solution
59
60By the time Perl 5 rolled around, we were already stuck with this
61design: Hash values must be scalars.  The solution to this is
62references.
63
64A reference is a scalar value that I<refers to> an entire array or an
65entire hash (or to just about anything else).  Names are one kind of
66reference that you're already familiar with.  Each human being is a
67messy, inconvenient collection of cells. But to refer to a particular
68human, for instance the first computer programmer, it isn't necessary to
69describe each of their cells; all you need is the easy, convenient
70scalar string "Ada Lovelace".
71
72References in Perl are like names for arrays and hashes.  They're
73Perl's private, internal names, so you can be sure they're
74unambiguous.  Unlike a human name, a reference only refers to one
75thing, and you always know what it refers to.  If you have a reference
76to an array, you can recover the entire array from it.  If you have a
77reference to a hash, you can recover the entire hash.  But the
78reference is still an easy, compact scalar value.
79
80You can't have a hash whose values are arrays; hash values can only be
81scalars.  We're stuck with that.  But a single reference can refer to
82an entire array, and references are scalars, so you can have a hash of
83references to arrays, and it'll act a lot like a hash of arrays, and
84it'll be just as useful as a hash of arrays.
85
86We'll come back to this city-country problem later, after we've seen
87some syntax for managing references.
88
89
90=head1 Syntax
91
92There are just two ways to make a reference, and just two ways to use
93it once you have it.
94
95=head2 Making References
96
97=head3 B<Make Rule 1>
98
99If you put a C<\> in front of a variable, you get a
100reference to that variable.
101
102    $aref = \@array;         # $aref now holds a reference to @array
103    $href = \%hash;          # $href now holds a reference to %hash
104    $sref = \$scalar;        # $sref now holds a reference to $scalar
105
106Once the reference is stored in a variable like $aref or $href, you
107can copy it or store it just the same as any other scalar value:
108
109    $xy = $aref;             # $xy now holds a reference to @array
110    $p[3] = $href;           # $p[3] now holds a reference to %hash
111    $z = $p[3];              # $z now holds a reference to %hash
112
113
114These examples show how to make references to variables with names.
115Sometimes you want to make an array or a hash that doesn't have a
116name.  This is analogous to the way you like to be able to use the
117string C<"\n"> or the number 80 without having to store it in a named
118variable first.
119
120=head3 B<Make Rule 2>
121
122C<[ ITEMS ]> makes a new, anonymous array, and returns a reference to
123that array.  C<{ ITEMS }> makes a new, anonymous hash, and returns a
124reference to that hash.
125
126    $aref = [ 1, "foo", undef, 13 ];
127    # $aref now holds a reference to an array
128
129    $href = { APR => 4, AUG => 8 };
130    # $href now holds a reference to a hash
131
132
133The references you get from rule 2 are the same kind of
134references that you get from rule 1:
135
136	# This:
137	$aref = [ 1, 2, 3 ];
138
139	# Does the same as this:
140	@array = (1, 2, 3);
141	$aref = \@array;
142
143
144The first line is an abbreviation for the following two lines, except
145that it doesn't create the superfluous array variable C<@array>.
146
147If you write just C<[]>, you get a new, empty anonymous array.
148If you write just C<{}>, you get a new, empty anonymous hash.
149
150
151=head2 Using References
152
153What can you do with a reference once you have it?  It's a scalar
154value, and we've seen that you can store it as a scalar and get it back
155again just like any scalar.  There are just two more ways to use it:
156
157=head3 B<Use Rule 1>
158
159You can always use an array reference, in curly braces, in place of
160the name of an array.  For example, C<@{$aref}> instead of C<@array>.
161
162Here are some examples of that:
163
164Arrays:
165
166
167	@a		@{$aref}		An array
168	reverse @a	reverse @{$aref}	Reverse the array
169	$a[3]		${$aref}[3]		An element of the array
170	$a[3] = 17;	${$aref}[3] = 17	Assigning an element
171
172
173On each line are two expressions that do the same thing.  The
174left-hand versions operate on the array C<@a>.  The right-hand
175versions operate on the array that is referred to by C<$aref>.  Once
176they find the array they're operating on, both versions do the same
177things to the arrays.
178
179Using a hash reference is I<exactly> the same:
180
181	%h		%{$href}	      A hash
182	keys %h		keys %{$href}	      Get the keys from the hash
183	$h{'red'}	${$href}{'red'}	      An element of the hash
184	$h{'red'} = 17	${$href}{'red'} = 17  Assigning an element
185
186Whatever you want to do with a reference, B<Use Rule 1> tells you how
187to do it.  You just write the Perl code that you would have written
188for doing the same thing to a regular array or hash, and then replace
189the array or hash name with C<{$reference}>.  "How do I loop over an
190array when all I have is a reference?"  Well, to loop over an array, you
191would write
192
193        for my $element (@array) {
194          ...
195        }
196
197so replace the array name, C<@array>, with the reference:
198
199        for my $element (@{$aref}) {
200          ...
201        }
202
203"How do I print out the contents of a hash when all I have is a
204reference?"  First write the code for printing out a hash:
205
206        for my $key (keys %hash) {
207          print "$key => $hash{$key}\n";
208        }
209
210And then replace the hash name with the reference:
211
212        for my $key (keys %{$href}) {
213          print "$key => ${$href}{$key}\n";
214        }
215
216=head3 B<Use Rule 2>
217
218L<B<Use Rule 1>|/B<Use Rule 1>> is all you really need, because it tells
219you how to do absolutely everything you ever need to do with references.
220But the most common thing to do with an array or a hash is to extract a
221single element, and the L<B<Use Rule 1>|/B<Use Rule 1>> notation is
222cumbersome.  So there is an abbreviation.
223
224C<${$aref}[3]> is too hard to read, so you can write C<< $aref->[3] >>
225instead.
226
227C<${$href}{red}> is too hard to read, so you can write
228C<< $href->{red} >> instead.
229
230If C<$aref> holds a reference to an array, then C<< $aref->[3] >> is
231the fourth element of the array.  Don't confuse this with C<$aref[3]>,
232which is the fourth element of a totally different array, one
233deceptively named C<@aref>.  C<$aref> and C<@aref> are unrelated the
234same way that C<$item> and C<@item> are.
235
236Similarly, C<< $href->{'red'} >> is part of the hash referred to by
237the scalar variable C<$href>, perhaps even one with no name.
238C<$href{'red'}> is part of the deceptively named C<%href> hash.  It's
239easy to forget to leave out the C<< -> >>, and if you do, you'll get
240bizarre results when your program gets array and hash elements out of
241totally unexpected hashes and arrays that weren't the ones you wanted
242to use.
243
244
245=head2 An Example
246
247Let's see a quick example of how all this is useful.
248
249First, remember that C<[1, 2, 3]> makes an anonymous array containing
250C<(1, 2, 3)>, and gives you a reference to that array.
251
252Now think about
253
254	@a = ( [1, 2, 3],
255               [4, 5, 6],
256	       [7, 8, 9]
257             );
258
259C<@a> is an array with three elements, and each one is a reference to
260another array.
261
262C<$a[1]> is one of these references.  It refers to an array, the array
263containing C<(4, 5, 6)>, and because it is a reference to an array,
264L<B<Use Rule 2>|/B<Use Rule 2>> says that we can write C<< $a[1]->[2] >>
265to get the third element from that array.  C<< $a[1]->[2] >> is the 6.
266Similarly, C<< $a[0]->[1] >> is the 2.  What we have here is like a
267two-dimensional array; you can write C<< $a[ROW]->[COLUMN] >> to get or
268set the element in any row and any column of the array.
269
270The notation still looks a little cumbersome, so there's one more
271abbreviation:
272
273=head2 Arrow Rule
274
275In between two B<subscripts>, the arrow is optional.
276
277Instead of C<< $a[1]->[2] >>, we can write C<$a[1][2]>; it means the
278same thing.  Instead of C<< $a[0]->[1] = 23 >>, we can write
279C<$a[0][1] = 23>; it means the same thing.
280
281Now it really looks like two-dimensional arrays!
282
283You can see why the arrows are important.  Without them, we would have
284had to write C<${$a[1]}[2]> instead of C<$a[1][2]>.  For
285three-dimensional arrays, they let us write C<$x[2][3][5]> instead of
286the unreadable C<${${$x[2]}[3]}[5]>.
287
288=head1 Solution
289
290Here's the answer to the problem I posed earlier, of reformatting a
291file of city and country names.
292
293    1   my %table;
294
295    2   while (<>) {
296    3     chomp;
297    4     my ($city, $country) = split /, /;
298    5     $table{$country} = [] unless exists $table{$country};
299    6     push @{$table{$country}}, $city;
300    7   }
301
302    8   for my $country (sort keys %table) {
303    9     print "$country: ";
304   10     my @cities = @{$table{$country}};
305   11     print join ', ', sort @cities;
306   12     print ".\n";
307   13	}
308
309
310The program has two pieces: Lines 2-7 read the input and build a data
311structure, and lines 8-13 analyze the data and print out the report.
312We're going to have a hash, C<%table>, whose keys are country names,
313and whose values are references to arrays of city names.  The data
314structure will look like this:
315
316
317           %table
318        +-------+---+
319        |       |   |   +-----------+--------+
320        |Germany| *---->| Frankfurt | Berlin |
321        |       |   |   +-----------+--------+
322        +-------+---+
323        |       |   |   +----------+
324        |Finland| *---->| Helsinki |
325        |       |   |   +----------+
326        +-------+---+
327        |       |   |   +---------+------------+----------+
328        |  USA  | *---->| Chicago | Washington | New York |
329        |       |   |   +---------+------------+----------+
330        +-------+---+
331
332We'll look at output first.  Supposing we already have this structure,
333how do we print it out?
334
335    8   for my $country (sort keys %table) {
336    9     print "$country: ";
337   10     my @cities = @{$table{$country}};
338   11     print join ', ', sort @cities;
339   12     print ".\n";
340   13	}
341
342C<%table> is an ordinary hash, and we get a list of keys from it, sort
343the keys, and loop over the keys as usual.  The only use of references
344is in line 10.  C<$table{$country}> looks up the key C<$country> in the
345hash and gets the value, which is a reference to an array of cities in
346that country.  L<B<Use Rule 1>|/B<Use Rule 1>> says that we can recover
347the array by saying C<@{$table{$country}}>.  Line 10 is just like
348
349	@cities = @array;
350
351except that the name C<array> has been replaced by the reference
352C<{$table{$country}}>.  The C<@> tells Perl to get the entire array.
353Having gotten the list of cities, we sort it, join it, and print it
354out as usual.
355
356Lines 2-7 are responsible for building the structure in the first
357place.  Here they are again:
358
359    2   while (<>) {
360    3     chomp;
361    4     my ($city, $country) = split /, /;
362    5     $table{$country} = [] unless exists $table{$country};
363    6     push @{$table{$country}}, $city;
364    7   }
365
366Lines 2-4 acquire a city and country name.  Line 5 looks to see if the
367country is already present as a key in the hash.  If it's not, the
368program uses the C<[]> notation (L<B<Make Rule 2>|/B<Make Rule 2>>) to
369manufacture a new, empty anonymous array of cities, and installs a
370reference to it into the hash under the appropriate key.
371
372Line 6 installs the city name into the appropriate array.
373C<$table{$country}> now holds a reference to the array of cities seen
374in that country so far.  Line 6 is exactly like
375
376	push @array, $city;
377
378except that the name C<array> has been replaced by the reference
379C<{$table{$country}}>.  The L<C<push>|perlfunc/push ARRAY,LIST> adds a
380city name to the end of the referred-to array.
381
382There's one fine point I skipped.  Line 5 is unnecessary, and we can
383get rid of it.
384
385    2   while (<>) {
386    3     chomp;
387    4     my ($city, $country) = split /, /;
388    5   ####  $table{$country} = [] unless exists $table{$country};
389    6     push @{$table{$country}}, $city;
390    7   }
391
392If there's already an entry in C<%table> for the current C<$country>,
393then nothing is different.  Line 6 will locate the value in
394C<$table{$country}>, which is a reference to an array, and push C<$city>
395into the array.  But what does it do when C<$country> holds a key, say
396C<Greece>, that is not yet in C<%table>?
397
398This is Perl, so it does the exact right thing.  It sees that you want
399to push C<Athens> onto an array that doesn't exist, so it helpfully
400makes a new, empty, anonymous array for you, installs it into
401C<%table>, and then pushes C<Athens> onto it.  This is called
402I<autovivification>--bringing things to life automatically.  Perl saw
403that the key wasn't in the hash, so it created a new hash entry
404automatically. Perl saw that you wanted to use the hash value as an
405array, so it created a new empty array and installed a reference to it
406in the hash automatically.  And as usual, Perl made the array one
407element longer to hold the new city name.
408
409=head1 The Rest
410
411I promised to give you 90% of the benefit with 10% of the details, and
412that means I left out 90% of the details.  Now that you have an
413overview of the important parts, it should be easier to read the
414L<perlref> manual page, which discusses 100% of the details.
415
416Some of the highlights of L<perlref>:
417
418=over 4
419
420=item *
421
422You can make references to anything, including scalars, functions, and
423other references.
424
425=item *
426
427In L<B<Use Rule 1>|/B<Use Rule 1>>, you can omit the curly brackets
428whenever the thing inside them is an atomic scalar variable like
429C<$aref>.  For example, C<@$aref> is the same as C<@{$aref}>, and
430C<$$aref[1]> is the same as C<${$aref}[1]>.  If you're just starting
431out, you may want to adopt the habit of always including the curly
432brackets.
433
434=item *
435
436This doesn't copy the underlying array:
437
438        $aref2 = $aref1;
439
440You get two references to the same array.  If you modify
441C<< $aref1->[23] >> and then look at
442C<< $aref2->[23] >> you'll see the change.
443
444To copy the array, use
445
446        $aref2 = [@{$aref1}];
447
448This uses C<[...]> notation to create a new anonymous array, and
449C<$aref2> is assigned a reference to the new array.  The new array is
450initialized with the contents of the array referred to by C<$aref1>.
451
452Similarly, to copy an anonymous hash, you can use
453
454        $href2 = {%{$href1}};
455
456=item *
457
458To see if a variable contains a reference, use the
459L<C<ref>|perlfunc/ref EXPR> function.  It returns true if its argument
460is a reference.  Actually it's a little better than that: It returns
461C<HASH> for hash references and C<ARRAY> for array references.
462
463=item *
464
465If you try to use a reference like a string, you get strings like
466
467	ARRAY(0x80f5dec)   or    HASH(0x826afc0)
468
469If you ever see a string that looks like this, you'll know you
470printed out a reference by mistake.
471
472A side effect of this representation is that you can use
473L<C<eq>|perlop/Equality Operators> to see if two references refer to the
474same thing.  (But you should usually use
475L<C<==>|perlop/Equality Operators> instead because it's much faster.)
476
477=item *
478
479You can use a string as if it were a reference.  If you use the string
480C<"foo"> as an array reference, it's taken to be a reference to the
481array C<@foo>.  This is called a I<symbolic reference>.  The declaration
482L<C<use strict 'refs'>|strict> disables this feature, which can cause
483all sorts of trouble if you use it by accident.
484
485=back
486
487You might prefer to go on to L<perllol> instead of L<perlref>; it
488discusses lists of lists and multidimensional arrays in detail.  After
489that, you should move on to L<perldsc>; it's a Data Structure Cookbook
490that shows recipes for using and printing out arrays of hashes, hashes
491of arrays, and other kinds of data.
492
493=head1 Summary
494
495Everyone needs compound data structures, and in Perl the way you get
496them is with references.  There are four important rules for managing
497references: Two for making references and two for using them.  Once
498you know these rules you can do most of the important things you need
499to do with references.
500
501=head1 Credits
502
503Author: Mark Jason Dominus, Plover Systems (C<mjd-perl-ref+@plover.com>)
504
505This article originally appeared in I<The Perl Journal>
506( L<http://www.tpj.com/> ) volume 3, #2.  Reprinted with permission.
507
508The original title was I<Understand References Today>.
509
510=head2 Distribution Conditions
511
512Copyright 1998 The Perl Journal.
513
514This documentation is free; you can redistribute it and/or modify it
515under the same terms as Perl itself.
516
517Irrespective of its distribution, all code examples in these files are
518hereby placed into the public domain.  You are permitted and
519encouraged to use this code in your own programs for fun or for profit
520as you see fit.  A simple comment in the code giving credit would be
521courteous but is not required.
522
523
524
525
526=cut
527