1
2#
3# Test of update statement that uses many tables,
4# --max_heap_table_size=1
5#
6
7--disable_warnings
8drop table if exists t1, t2;
9--enable_warnings
10
11--echo #
12--echo # Bug #36676: multiupdate using LEFT JOIN updates only
13--echo #             first row or fails with an error:
14--echo #  ERROR 1022 (23000): Can't write; duplicate key in table ''
15--echo #
16
17--echo
18
19--echo #
20--echo # Multiupdate creates MyISAM temporary table without MEMORY table
21--echo #
22
23CREATE TABLE t1 (ID INT);
24CREATE TABLE t2 (ID INT,
25  s1 TEXT, s2 TEXT, s3 VARCHAR(10), s4 TEXT, s5 VARCHAR(10));
26
27INSERT INTO t1 VALUES (1),(2);
28INSERT INTO t2 VALUES (1,'test', 'test', 'test', 'test', 'test'),
29                      (2,'test', 'test', 'test', 'test', 'test');
30
31SELECT * FROM t1 LEFT JOIN t2 USING(ID);
32UPDATE t1 LEFT JOIN t2 USING(ID) SET s1 = 'changed';
33UPDATE t1 JOIN t2 USING(ID) SET s2 = 'changed';
34UPDATE t1 LEFT JOIN t2 USING(ID) SET s3 = 'changed';
35UPDATE t1 LEFT JOIN t2 USING(ID) SET s4 = 'changed', s5 = 'changed';
36SELECT * FROM t1 LEFT JOIN t2 USING(ID);
37
38DROP TABLE t1, t2;
39
40--echo #
41--echo # Multiupdate creates temporary MyISAM table from MEMORY table
42--echo #
43
44CREATE TABLE t1 (id INT NOT NULL AUTO_INCREMENT PRIMARY KEY);
45CREATE TABLE t2 (id INT, s1 CHAR(255));
46
47# insert [1..64] into table `t1`
48INSERT INTO t1 VALUES (0), (0), (0), (0), (0), (0), (0), (0);
49INSERT INTO t1 (SELECT 0 FROM t1);
50INSERT INTO t1 (SELECT 0 FROM t1);
51INSERT INTO t1 (SELECT 0 FROM t1);
52
53INSERT INTO t2 (SELECT ID, 'a' FROM t1);
54
55UPDATE t1 LEFT JOIN t2 USING(id) SET s1 = 'b';
56
57SELECT DISTINCT s1 FROM t1 LEFT JOIN t2 USING(id);
58
59DROP TABLE t1, t2;
60
61
62--echo # End of 5.0 tests
63