1 /* ========================================================================== */
2 /* === ldlsimple.c:  a simple LDL main program ============================== */
3 /* ========================================================================== */
4 
5 /* LDLSIMPLE:  this is a very simple main program that illustrates the basic
6  * usage of the LDL routines.  The output of this program is in ldlsimple.out.
7  * This program factorizes the matrix
8  *
9  *    A =[ ...
10  *    1.7     0     0     0     0     0     0     0   .13     0
11  *      0    1.     0     0   .02     0     0     0     0   .01
12  *      0     0   1.5     0     0     0     0     0     0     0
13  *      0     0     0   1.1     0     0     0     0     0     0
14  *      0   .02     0     0   2.6     0   .16   .09   .52   .53
15  *      0     0     0     0     0   1.2     0     0     0     0
16  *      0     0     0     0   .16     0   1.3     0     0   .56
17  *      0     0     0     0   .09     0     0   1.6   .11     0
18  *    .13     0     0     0   .52     0     0   .11   1.4     0
19  *      0   .01     0     0   .53     0   .56     0     0   3.1 ] ;
20  *
21  * and then solves a system Ax=b whose true solution is
22  * x = [.1 .2 .3 .4 .5 .6 .7 .8 .9 1]' ;
23  *
24  * Note that Li and Lx are statically allocated, with length 13.  This is just
25  * enough to hold the factor L, but normally this size is not known until after
26  * ldl_symbolic has analyzed the matrix.  The size of Li and Lx must be greater
27  * than or equal to lnz = Lp [N], which is 13 for this matrix L.
28  *
29  * Copyright (c) 2006 by Timothy A Davis, http://www.suitesparse.com.
30  * All Rights Reserved.  See LDL/Doc/License.txt for the License.
31  */
32 
33 #include <stdio.h>
34 #include "ldl.h"
35 #define N 10	/* A is 10-by-10 */
36 #define ANZ 19	/* # of nonzeros on diagonal and upper triangular part of A */
37 #define LNZ 13	/* # of nonzeros below the diagonal of L */
38 
main(void)39 int main (void)
40 {
41     /* only the upper triangular part of A is required */
42     int    Ap [N+1] = {0, 1, 2, 3, 4,   6, 7,   9,   11,      15,     ANZ},
43            Ai [ANZ] = {0, 1, 2, 3, 1,4, 5, 4,6, 4,7, 0,4,7,8, 1,4,6,9 } ;
44     double Ax [ANZ] = {1.7, 1., 1.5, 1.1, .02,2.6, 1.2, .16,1.3, .09,1.6,
45 		     .13,.52,.11,1.4, .01,.53,.56,3.1},
46            b [N] = {.287, .22, .45, .44, 2.486, .72, 1.55, 1.424, 1.621, 3.759};
47     double Lx [LNZ], D [N], Y [N] ;
48     int Li [LNZ], Lp [N+1], Parent [N], Lnz [N], Flag [N], Pattern [N], d, i ;
49 
50     /* factorize A into LDL' (P and Pinv not used) */
51     ldl_symbolic (N, Ap, Ai, Lp, Parent, Lnz, Flag, NULL, NULL) ;
52     printf ("Nonzeros in L, excluding diagonal: %d\n", Lp [N]) ;
53     d = ldl_numeric (N, Ap, Ai, Ax, Lp, Parent, Lnz, Li, Lx, D, Y, Pattern,
54 	Flag, NULL, NULL) ;
55 
56     if (d == N)
57     {
58 	/* solve Ax=b, overwriting b with the solution x */
59 	ldl_lsolve (N, b, Lp, Li, Lx) ;
60 	ldl_dsolve (N, b, D) ;
61 	ldl_ltsolve (N, b, Lp, Li, Lx) ;
62 	for (i = 0 ; i < N ; i++) printf ("x [%d] = %g\n", i, b [i]) ;
63     }
64     else
65     {
66 	printf ("ldl_numeric failed, D (%d,%d) is zero\n", d, d) ;
67     }
68     return (0) ;
69 }
70