1 #include "tinyexpr.h" 2 #include <stdio.h> 3 main(int argc,char * argv[])4 int main(int argc, char *argv[]) 5 { 6 const char *c = "sqrt(5^2+7^2+11^2+(8-2)^2)"; 7 double r = te_interp(c, 0); 8 printf("The expression:\n\t%s\nevaluates to:\n\t%f\n", c, r); 9 return 0; 10 } 11