1 #include "tinyexpr.h"
2 #include <stdio.h>
3 
main(int argc,char * argv[])4 int main(int argc, char *argv[])
5 {
6     const char *c = "sqrt(5^2+7^2+11^2+(8-2)^2)";
7     double r = te_interp(c, 0);
8     printf("The expression:\n\t%s\nevaluates to:\n\t%f\n", c, r);
9     return 0;
10 }
11