1 /*
2  * Copyright (c) 1998, 2001, Oracle and/or its affiliates. All rights reserved.
3  * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
4  *
5  * This code is free software; you can redistribute it and/or modify it
6  * under the terms of the GNU General Public License version 2 only, as
7  * published by the Free Software Foundation.  Oracle designates this
8  * particular file as subject to the "Classpath" exception as provided
9  * by Oracle in the LICENSE file that accompanied this code.
10  *
11  * This code is distributed in the hope that it will be useful, but WITHOUT
12  * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
13  * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
14  * version 2 for more details (a copy is included in the LICENSE file that
15  * accompanied this code).
16  *
17  * You should have received a copy of the GNU General Public License version
18  * 2 along with this work; if not, write to the Free Software Foundation,
19  * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
20  *
21  * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
22  * or visit www.oracle.com if you need additional information or have any
23  * questions.
24  */
25 
26 /* ilogb(double x)
27  * return the binary exponent of non-zero x
28  * ilogb(0) = 0x80000001
29  * ilogb(inf/NaN) = 0x7fffffff (no signal is raised)
30  */
31 
32 #include "fdlibm.h"
33 
34 #ifdef __STDC__
ilogb(double x)35         int ilogb(double x)
36 #else
37         int ilogb(x)
38         double x;
39 #endif
40 {
41         int hx,lx,ix;
42 
43         hx  = (__HI(x))&0x7fffffff;     /* high word of x */
44         if(hx<0x00100000) {
45             lx = __LO(x);
46             if((hx|lx)==0)
47                 return 0x80000001;      /* ilogb(0) = 0x80000001 */
48             else                        /* subnormal x */
49                 if(hx==0) {
50                     for (ix = -1043; lx>0; lx<<=1) ix -=1;
51                 } else {
52                     for (ix = -1022,hx<<=11; hx>0; hx<<=1) ix -=1;
53                 }
54             return ix;
55         }
56         else if (hx<0x7ff00000) return (hx>>20)-1023;
57         else return 0x7fffffff;
58 }
59